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I would love to talk to you about this one
go to http://www.scribblar.com/mg9yqg9
to get my email address. You are missing the negation symbols like for stop going places would be -g where - is the negation symbol.
email me and we will talk

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email me and I will work this one out with you in an online whiteboard.
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Basically, we are dealing with a quadratic function. Generally, that will involve using the "vertex form"

so, we know that there is a maximum of y=35. what, in the formula, is the y value of the vertex of the parabola? (b)
Since the y values are the same on the given points, then the axis of symmetry is in the middle of them (2+10)/2 or 6. that is the h value of the vertex. If they were not the same y values, then we could still find the h value, but it would be more complicated:
.
.
***alternative way to find h value Start***
.
so we can insert that into the formula: y=a(x-h)^2+35
we also know two points that work. enter the first point and you get 3=a(2-h)^2+35
foil (2-h)^2 to get h^2-4h+4,
solve for "a"
a=-32/(h^2-4h+4)
.
now plug the other point into y=a(x-h)^2+35
and you get 3=a(10-h)^2+35
subtract 35 from both sides
-32=a(10-h)^2
substitute -32/(h^2-4h+4) from the first equation in for a in the second equation.
You get:
-32=(-32(10-h)^2)/(h^2-4h+4)
reduce the -32's and move the h^2-4h+4 to the left
reduce to find the h value.
h=6
***alternative way to find h value Stop***
.
.
so now you have y=a(x-6)^2+35
use one of the points for the x and y value to find "a"
3=a(4)^2+35
-32/16=a
a=-2
so
y=-2(x-6)^2+35

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send me an email and I will send you a link to a whiteboard.

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I am guessing that you want to find the zeros or how to factor it.
It factors to (b-10)(b-8)
If you want to ask more specific questions, then get my email address from http://www.scribblar.com/mg9yqg9 and ask away.

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go to http://www.scribblar.com/mg9yqg9 for my email address, send me an email and I will answer this.
basically, you don't use logarithms...if that is what you are trying to do. You can get rid of the negative exponent by moving it to the bottom and making it positive (hopefully this jogs your memory on that).
So basically, you get
Then multiply both sides by and divide both sides by .035 and you get
cube both sides to find d
send the answer to my email address listed on scribblar and I will verify the answer.
ps There are other ways/techniques of solving this as well.

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Yes, it is a linear equation.
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square root the top and the bottom

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Combine the two logarithms into a single logarithm
log[(x+9)/x]=3
rewrite in exponential form

solve for x

1000x=x+9
999x=9

Verify this in your calculator by substituting 1/111 in for x.
Let me know if you have any other questions.
Justin

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yes, but "systems" usually contain 2 or more equations. Is there more to the problem or do you just have to write an equation? Also, you might identify your variables and say that x is your larger number and y is the smaller number. Do you know what the 2 numbers sum is or anything else? If so, then you could write another equation and then solve the system.
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Let q be the number of quarters and n be the number of nickels. The most important thing here is to understand that q is the NUMBER of nickels, not how much they are worth (same with q and quarters).
so, .25q+.05n=4
now we need to look at the relationship of quarters to nickels. It is tricky sometimes to write this part, is it 3n=q or 3q=n??? I read this as she has more quarters than nickels, (3 times as many to be exact). So which one would make the number of quarters larger than the number of nickels? 3n=q
I would use substitution at this point.
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using the subtraction property of logarithms, we can combine the two logarithms and get log base 5 [(3x-1)/(x+5)]=0
Then, we can rewrite the problem in exponential form.
I always say "a to the b equals c" for a general exponential form and then drop the a down to the base, move the "b" to the right side of the equals sign, and then move the c to the left. It looks something like this:
Exponential form:
Logarithm form: log base a of c=b
So, in this case, our "a" is 5, our "b" is 0 and our "c" is
and we can write it in exponential form:

well, because of the zero exponent property and therefore
Multiply both sides by (x+5) and then solve for x
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The range (possible y values) is (-8,7]

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You are correct.
rewrite sqrt(x) as x^(1/2) and then when you multiply like bases, we add the exponents, so we get 4+1/2=9/2
the domain is because you can not get a real answer by taking the square root of a negative number.

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I can help at http://www.scribblar.com/whh9htqcx
This is a free browser based online whiteboard.
The answer is (-2,0), but I will show the work at the above link.

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I think you have something written wrong, we know nothing about v

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-11

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17a-a
simplifies to: 16a

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Let the Perimeter of the square be P=4s
Then the Perimeter of the triangle is P+7=3(s+5)
Substitute
4s+7=3(s+5)
4s+7=3s+15
s=8
Here is an online whiteboard that I use while I am working problems on algebra.com. Although you can access it anytime, I only monitor it while I am working problems. http://www.scribblar.com/whh9htqcx
I am working on your problem right now and will update this answer within the next 5-15 minutes, but if you want to see additional information or talk to me while I work it out, then go to the link above.

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This is all places where y=-4. So go straight down on the vertical (up and down) axis and you will find the value where y=-4, but y=-4 anywhere to the left or right of that point also, so the line y=-4 is all of those values. The slope is 0.
Here is an online whiteboard that I use while I am working problems on algebra.com. Although you can access it anytime, I only monitor it while I am working problems. http://www.scribblar.com/whh9htqcx

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That depends on the graph.
Here is an online whiteboard that I use while I am working problems on algebra.com. Although you can access it anytime, I only monitor it while I am working problems. http://www.scribblar.com/whh9htqcx

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logaX=loga(y/z)
0=loga(y/z)-logaX
0=loga(y/(xz))
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3-first term
2-second term
1-third term
0-fourth term
3-polynomial

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=6

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There are different methods of solving this, but the first step is to plot all the points on a graph. Next, you can either use the distance formula, simply count the squares, or use the pythagorean theorem. You can count squares for all but 1 side and I would recommend using the pythagorean theorem to find that side.
The side lengths are 5,4,2,5
therefore, the perimeter is the distance around the quadrilateral, which is
5+4+2+5=16. There may be units for this as well, so make sure you include units.

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The discriminant is what is under the square root sign of the quadratic equation: if the discriminant is positive, then there are 2 real solutions, if it is 0, then there is 1 real solution, and if it is negative, then it has 2 imaginary solutions.
Let me know if this helps.

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natural numbers are numbers we count with. We don't count with 0, so 0 is not included. (1,2,3,4...)
whole numbers add the 0 to the natural numbers, so (0,1,2,3,...)
Integers include negative numbers (-2,-1,0,1,2,...)
rationals can be written as a fraction of two integers a and b (-a/b, a/b...)
irrationals can not be written as a fraction. They are non repeating numbers like the square root of 2 or pi
real numbers include all rationals, irrationals and everything. They do not include square root of negative numbers though.
Hope this helps.

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substitute -7 for z into the expression. Put parenthesis around it so you don't get confused.
I think that you may have your expression written wrong, so I am hesitant to solve this for you.
will equal is different than
the second equation will be equal to 1, the first equation will be a fraction

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Hi, you forgot to include the equation for this problem. Substitute x=1 into the equation and solve to find the answer to 51, x=3 and solve for the answer to 52, x=6 and solve for the answer to 53, x=12 and solve for answer to 54 and then plot the answers on a graph with the x axis (the horizontal left to right line) having 12 marks each representing 1 month (label the x axis "x months") and then the y axis will be the number of fish.
Hope this helps.

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in an inequality , , , , when you divide both sides of the inequality by a negative then you have to flip the inequality. so:

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the first 2 terms (1 and 1) are given, and then each term is the sum of the two terms before it.
So
1 =given
1 =given
2=1+1
3+2+1
5=3+2
8=5+3
13=5+8
_=13+8
_=_+_

I think this should help, but leave me a comment and let me know.

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you can add the x squared terms together, the x terms together and the constant terms together. In order to add fractions you need to get a common denominator, so 2/3 + 1/6 would need to be 4/6 + 1/6=5/6
-1/3 + 1/2 = -2/6 +3/6 =1/6, so your x^2 term will be
Do this with the other terms as well. Be careful though when you subtract, because you will need to distribute the negative throughout the parenthesis and then combine the like terms.