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Recent problems solved by 'Kaloda'

Kaloda answered: 2 problems

Expressions-with-variables/406013: what value of x will make x+5=2x+10 true?
1 solutions

Answer 286623 by Kaloda(2) on 2011-02-08 05:32:13 (Show Source):

You can put this solution on YOUR website!
x+5=2x+10
2x-x=5-10
final answer:
x = -5

Polynomials-and-rational-expressions/406015: The area of a rectangle is three times the area of a square. If the rectangle is 15 inches long, and the width of the rectangle is the same as the length of a side of the square, find the dimensions of both the rectangle and the square.
1 solutions

Answer 286622 by Kaloda(2) on 2011-02-08 05:30:16 (Show Source):

You can put this solution on YOUR website!
let, A = area of rectangle
B = area of the square
l = length of the rectangle
w = width of the rectangle
s = side of the square
A = 3B
l = 15
w = s
A = l.w = 3B
15s = 3s^2
3s^2 - 15s = 0
s^2 - 5s = 0
s^2 - 5s + 25/4 = 25/4
(s - 5/2)^2 = 25/4
s - 5/2 = 5/2
Final answers:
s = 5
w = 5
l = 15

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Recent problems solved by 'Kaloda'