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N(t)=N base0e^kt, given that N(0)=1 and N(3)=7. thanks in advance. 1 solutions
Answer 78826 by Fombitz(13828) on 2007-11-05 15:05:24 (Show Source):
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Radicals/108172: Would you please help me with this problem
The questions is to simplify and combine like radicals. All variables represent positive numbers.
sqrt2 - sqrt8
My results
sqrt2 = 1*2
sqrt8 = 2*2*2
answer -sqrt4 ( I was told that this is the wrong answer)
Please help!!! 1 solutions
Answer 78825 by Fombitz(13828) on 2007-11-05 14:57:34 (Show Source):
You can put this solution on YOUR website!Let's start from your results
sqrt2 = 1*2
sqrt8 = 2*2*2
Your right hand side should still include the square root.
sqrt2 = sqrt(1*2)
sqrt8 = sqrt(2*2*2)
Then
sqrt2 = sqrt(2)
sqrt8 = sqrt(2*2)*sqrt(2)
and you can substitute since
sqrt(2*2) = 2
Your equations then become
sqrt2 = sqrt(2)
sqrt8 = 2*sqrt(2)
Now your subtraction can take place.
sqrt2 - sqrt8 = sqrt2 - 2*sqrt(2)
sqrt2 - sqrt8 = -sqrt(2)
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logarithm/108166: can anyone help me?:determine the horizontal asymptote of the graph of
B(t)=1200/1+34e^-0.125t. i have no idea how to solve this. 1 solutions
Answer 78824 by Fombitz(13828) on 2007-11-05 14:51:27 (Show Source):
You can put this solution on YOUR website!You can do it two ways.
Graphically or by analysis.
Let's do analysis.
As t gets large, since there is a -.125 coefficient to multiply t in the exponential, the exponential function drops quickly to zero.
Then function then looks like
 for large positive t.
Example: At t=100, B(t)=1199.848
I'm not sure of the context of this function, that is if t is always positive, like time.
If not, we can look at what happens when t becomes large in the negative direction.
In that case (-.125t) becomes very large, and the exponential function becomes very large.
 for large negative t.
Example: At t=-100, B(t)=.000132
There is a horizontal asymptote at y=1200.
And if it makes sense in your problem, there is also one at y=0.
Graphically it's easier to find the asymptotes,
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logarithm/108167: what is the domain of f(x)=x+log(base)3(x-5). not sure if it is x>5 or x>0 of course i could be wrong for both . can someone help. 1 solutions
Answer 78822 by Fombitz(13828) on 2007-11-05 14:24:59 (Show Source):
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logarithm/108165: can anyone help me solve this: find the balance(to the nearest cent) if $24,000 is invested at an annual interest rate of 6.8% for 10 years compounded continuously. I have tried to solve 5 times but cannot come up with a reasonable answer. 1 solutions
Answer 78819 by Fombitz(13828) on 2007-11-05 14:16:35 (Show Source):
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Linear-equations/108162: HI please help me with this.THankyou
The equation 9C-5F+160=0 describes the relationship between tempreature,C, in degrees Celsiu, and the tempreature , F, in degrees fahrenheit.
a) express the equation in the form C=mF+b
b) Graph this relation
c) Identify the slope and the C intercept and explain what they mean 1 solutions
Answer 78817 by Fombitz(13828) on 2007-11-05 14:03:35 (Show Source):
You can put this solution on YOUR website!
 Add (5F-160) to both sides.
 Simplify.
 Divide both sides by 9.
a)  Simplify.
b)

c.) The slope is the number is the coefficient of F in equation a or 5/9.
It relates the rate of change in each temperature system.
For a change of 9 degrees Fahrenheit, you get a 5 degrees change in Celsius.
The C intercept is where the graph crosses the y axis. The value of C when F=0. C(0) is the equivalent temperature in Celsius to 0 F. In this case,
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Linear_Equations_And_Systems_Word_Problems/108124: Stan invested $17,000, part at 18% and part at 4%.
If the total interest at the end of the year is $1,380, how much did he invest at each
rate?
1 solutions
Answer 78802 by Fombitz(13828) on 2007-11-05 11:11:05 (Show Source):
You can put this solution on YOUR website!Let's call the part he invested at 18%, E, and the part he invested at 4%, F.
Then you know that,
1. 
2. 
Use 1. to solve for E in terms of F.
1.

Now substitute that into equation 2 and solve for F.
2.

From 1.

Verify your answer using equation 2.
 Close enough, round off error.
Good answer.
$4571.43 at 18%, $12428.57 at 4%.
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Inequalities/108126: please help me solve this equation x+3_>4 and -4x<20 1 solutions
Answer 78801 by Fombitz(13828) on 2007-11-05 11:01:13 (Show Source):
You can put this solution on YOUR website! x+3_>4 and -4x<20
First equation
 Subtract 3 from both sides.

Second equation
 Divide both sides by (-4), change direction of inequality.

Since you must satisfy both conditions
 and  , then the solution is
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Age_Word_Problems/108129: I am trying to help my daughter but we cannot set up this problem can you please help us thank you.
For six consecutive years a man's age was a multiple of his granddaugters age. How old was each during the sixth year? 1 solutions
Answer 78798 by Fombitz(13828) on 2007-11-05 10:49:52 (Show Source):
You can put this solution on YOUR website!Let's call the Grandfather's age, X, and the Grandaughter's age Y.
The first year X=mY where m is an integer (1,2,3,4,..)
and for the next 5 years,
X+1=n(Y+1)
X+2=o(Y+2)
X+3=p(Y+3)
X+4=q(Y+4)
X+5=r(Y+5)
where n,o,p,q,and r are also integers.
Using this method you have 6 equations, but you have 8 unknowns, so it doesn't help.
Another method is to look at the list of prime numbers, that is numbers that are divisible only by themselves and 1.
You need to find 6 consecutive non-prime or composite numbers.
The list of primes under 100 is
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97
The first time you have six consecutive divisible numbers starts at 90.
90=3x3x10
91=7x13
92=2x2x23
93=3x31
94=2x47
95=5x19
96=2x2x24
The issue is that 93,94,95 have only prime factors and the factors are not consecutive, so they can't be the daughter's age.
The next 6 consecutive composite numbers start at 114 to 126.
The same issue exists as before
115,118,119,122,123,124 have large prime factors in them and cannot be the daughter's age.
I don't believe there's a solution to this problem, as stated.
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Radicals/107625: Multiply:
(8√[6] + 3√[2])(4√[6] – 5√[2])
I believe FOIL is used here. I also think the answer should have no decimals.
Thanks for helping!!! 1 solutions
Answer 78401 by Fombitz(13828) on 2007-11-02 11:32:37 (Show Source):
You can put this solution on YOUR website!Yes FOIL Method (First Outer Inner Last)
(8√[6] + 3√[2])(4√[6] + (-5√[2])) Original Equation
First (8√[6]*4√[6])=32√[36]
First (8√[6]*4√[6])=32*6
First (8√[6]*4√[6])=192
Outer (8√[6]*-5√[2])=-40√[12]
Outer (8√[6]*-5√[2])=-80√[3]
Inner (3√[2]*4√[6])=12√[12]
Inner (3√[2]*4√[6])=24√[3]
Last (3√[2]*-5√[2])=-15√[4]
Last (3√[2]*-5√[2])=-15*2
Last (3√[2]*-5√[2])=-30
(8√[6]+3√[2])(4√[6]+(-5√[2]))=192+(-80√[3])+24√[3]+(-30) Combine all of the terms
(8√[6]+3√[2])(4√[6]+(-5√[2]))=162-56√[3] Final answer.
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Equations/107634: Determine whether the equation is an identity, a conditional equation, or an inconsistant equation.
1/(x+5) + 2/(x+3) = -2/(x^2 + 8x +15) 1 solutions
Answer 78398 by Fombitz(13828) on 2007-11-02 11:11:51 (Show Source):
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Graphs/107633: This question is from textbook Blitzer
f(X)=2x+3
----
x+2
Find the Horizontal and Vertical asympotes. 1 solutions
Answer 78392 by Fombitz(13828) on 2007-11-02 10:56:03 (Show Source):
You can put this solution on YOUR website!The vertical asymptote occurs when the denominator goes to zero, that is,
f(x) goes to  and  .

The horizontal asymptotes occur as x goes to  and  .

As x goes to  ,
f(x) looks like  or 2.
As x goes to  ,
f(x) looks like  or 2.
The horizontal asymptote is y=2.
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Exponents/107638: problem: divide and simplify: (a^-2)^3(a^4)^2 / (a^3)^-3 this^and a number is the exponet please show how you come to your answer. 1 solutions
Answer 78390 by Fombitz(13828) on 2007-11-02 10:45:46 (Show Source):
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Polynomials-and-rational-expressions/107636: This question is from textbook
Please help:
One of my homework problems involves the following expression
(-8/27)^-2/3
The expression needs to be simplified.
I think the answer is 4/9, but I want to make sure I'm on the right track.
Thank you 1 solutions
Answer 78389 by Fombitz(13828) on 2007-11-02 10:39:09 (Show Source):
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Linear_Algebra/107512: I am trying to help my daughter with her homework, but since I have no idea what I am doing I hope that having the answer will help me out:
Cricket Problem: Based on information in Deep River Jim's Wilderness Trailbook, the rate at which crickets chirp is a lenear function of temperature. At 55 degrees F they make 70 chirps per minute and at 69 degrees F they make 126 chirps per minute.
a) Write the equation expressing chirping rate as a function of temperature.
b) Predict the chirping rate at 90 degrees F.
c) How warm is it if they are chirping 120 chirps per minute?
d) Calculate the temperature-intercept. What does this tell you about this numbeer in the real-world?
e) Calculate the chirping-intercept. What does the chirping-intercept tell you about the real-worl?
f) Shetch and label the graph.
Thank you for any help.
Brian 1 solutions
Answer 78289 by Fombitz(13828) on 2007-11-01 17:05:09 (Show Source):
You can put this solution on YOUR website!Linear equation means you need two points to calculate the equation.
You have two points.
Let C=chirp rate and T=temperature.
The equation of a line is given by,

where m is the slope of the line and b is the intercept.
The slope is given by

Using the two data points, you gave,
 and the units are chirps per minute/degree F.
You can solve for b by using m you just calculated and one data point.

The equation of your line is then

You can verify with your two points.

70 chirps at 55 degrees F. That checks out.

126 chirps at 69 degrees F. That checks out.
Your equation matches the data.
a.)C(T)=4T-150 where C is chirps per minute, T is degrees F.
Chirping rate at 90F.
C(90)=4(90)-150
C(90)=360-150
C(90)=210
b.)210 chirps per minute at 90 degrees F.
C(T)=4T-150=120
4T-150=120
4T-150+150=120+150
4T=270
T=270/4
c.)T=67.5 degrees F for 120 chirps per minute.
d.) The temperature intercept is where the chirping rate is equal to zero.
4T-120=0
4T-120+120=120
4T=120
T=30 degrees F.
In the real world, that says chirping doesn't start until 30 degrees.
The birds are probably conserving their energy because its so cold.
e.) The chirping intercept is where the temperature is equal to zero.
C(0)=4(0)-120=-120.
This doesn't really have a real world interpretation since there is no such thing as a negative chirp. Chirps need to be positive, that is not defined below T=30 degrees F.
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Rational-functions/107484: Solve the inequality 21/15-3x<0 and express the solution as an
interval.
a. (5, ∞)
b. (7, ∞)
c. (–∞,5)
d. (–∞, 7) 1 solutions
Answer 78286 by Fombitz(13828) on 2007-11-01 16:39:10 (Show Source):
You can put this solution on YOUR website!If 
then (15-3x)<0 since the numerator is positive.
 Add 3x to both sides.
 Divide both sides by 3.
 or

Check your answer.
Pick a number greater than 5. Let's pick 10.
The inequality should hold true since 10>5.

True statement. Good answer.
a. (5, ∞)
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Rational-functions/107480: If a piece of real estate purchased for $50,000 in 1998 appreciates at
the rate of 5% per year, then its value t years after the purchase will
be f (t) = 50,000(1.05t ) . According to this model, by how much will the
value of this piece of property increase between the years 2007 and
2008?
a. $2500
b. $3140
c. $3880
d. $31,400 1 solutions
Answer 78283 by Fombitz(13828) on 2007-11-01 16:30:11 (Show Source):
You can put this solution on YOUR website!First, a correction.
If the property appreciates 5% every year, then after the first year,1999.
F(1)=50000(1.05)
After the second year, 2000.
F(2)=F(1)*(1.05)=50000(1.05)(1.05)= 
The equation should be

then
2007 would be the 9th year and 2008 would be the 10th year.
 and

or
 and

The difference between the 10th year and the 9th year would then be

C.3880, close enough.
If you used the original equation, the house value increases only $2500,
after the first year but then increases value by $52,500 every year after.
At the end of the 10th year, the house would be worth $525,000.
That would be a great profit.
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