New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'Fombitz'
Fombitz answered: 13805 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829, >>Next
Matrices-and-determiminant/166219: can someone please help:
Determine whether the two matrices are inverses of each other by computing their product.
1.
2, -1, 0
-1, 1, -2
1, 0, -1
2.
1, -1, 2
-3, -2, 4
-1, 1, 1
yes or no 1 solutions
Answer 122505 by Fombitz(13828) on 2008-11-06 16:22:50 (Show Source):
You can put this solution on YOUR website!Multiply rows of the first matrix by columns of the second matrix to get the product.
Example: First entry of the product matrix,  ,

.
.
.
|
absolute-value/166117: Solve (|3x-1|) / (x²+4) ‹ 0. Give a written explanation along with algebraic support.
PLEASE HELP ME!!! 1 solutions
Answer 122478 by Fombitz(13828) on 2008-11-06 12:56:11 (Show Source):
You can put this solution on YOUR website!
The denominator is always positive.
The numerator is always positive or zero.
Therefore, there is no value of x such that the left hand side would be less than zero.
No solution.

By definition,
 for all Y.
.
.
.
Graphical verification.
|
Money_Word_Problems/166173: Would you rather have a kilometer of quarters or a kilometer of dimes? (in a straight line, with the heads up). How much better is your choice?
THANK YOU SO MUCH! 1 solutions
Answer 122467 by Fombitz(13828) on 2008-11-06 11:30:20 (Show Source):
You can put this solution on YOUR website!Well I guess we have to count how many of each are in a kilometer.
From a GOOGLE search, I found the following information,
dime:1.35 mm thickness
quarter:1.75 mm thickness
Let's assume it's correct.
So 1 km, which equals (1000)(1000)mm, there are this many dimes,

Each dime is $0.10, so the total in 1 km is,

Similarly for the quarters,

Fewer of them, but what about the total value,

Wow, it's almost double.
The exact difference is

$68,783 difference between the two coin kilometers.
That's a lot of coin wrappers!
|
Sequences-and-series/166155: How to derive Nth term of the following series?
1,3,6,10,15,21.........upto n terms 25!!!!!!!!!!!!!!!!!!!!!!!!! 1 solutions
Answer 122459 by Fombitz(13828) on 2008-11-06 10:19:10 (Show Source):
You can put this solution on YOUR website!Look at the difference between terms,
1,3=2
3,6=3
6,10=4
10,15=5
15,21=6
.
.
.
First term=1
Second term=First term +2=1+2
Third term=Second term+3=1+2+3
Fourth term=Third term+4=1+2+3+4
Starting to see a pattern here...
Nth term=(N-1)term+N=1+2+3+...+(N-1)+N
Look like the terms follow,
|
Complex_Numbers/166180: I'm not sure if this is the right section, but I will still ask.
1. Use synthetic division to find f(-3) for f(x)2x^3-6x^2-5x+7.
2. One factor of f(x)=x^3+x^2-22x-40 is x+4. Find the other factors.
I must show my work and have no textbook to explain. Will you PLEASE HELP!!!!
Thanks 1 solutions
Answer 122454 by Fombitz(13828) on 2008-11-06 09:55:09 (Show Source):
You can put this solution on YOUR website!1. You don't need synthetic division to find f(-3). Just substitute.

.
.
.
2. Here you need the synthetic division.
Showing synthetic division is a little difficult.
The first part will show the factor (left hand column), then the factor times the divisor,
then the next line will show the subtraction.
Repeat.
Hopefully it makes sense.
.
.
.
..........._______________
(x+4)|x^3+x^2-22x-40
x^2:...x^3+4x^2
..................-3x^2-22x-40
-3x:..........-3x^2-12x
.............................-10x-40
-10:......................-10x-40

Now you can factor the quadratic,

and substitute back,
|
Quadratic_Equations/166183: Please check my answers for in quadratic formula:
solve: v^2 = 12v - 24
v^2 12v + 24 = 0
v = 12 =/- sqr. rt. of 12^2 - 4(24)/2
= 12 +/- sqr. rt of 144 - 96/2
= 12 sqr. rt of 48/2
= 12 sqr. rt. of 4*4*3/2
= 12 +/- 4 sqr. rt. of 3/2
answer: 6 - 4 sqrt rt. of 3, 6 + 4 sqr. rt. of 3
1 solutions
Answer 122451 by Fombitz(13828) on 2008-11-06 09:45:53 (Show Source):
|
Quadratic-relations-and-conic-sections/166176: Can anybody tell me if I have identified these correctly? I'm not sure.
Thanks!!!
a) (x-3)^2/9 + (y-2)^2/4 = 1 ellipse
b) (x+2)^2/25 - (y-1)^2/9 = 1 hyperbola
c) x^2 + 4x = y - 4 parabola
d) (x + 2)^2 + (y-3)^2 = 49 circle
e) (x + 1)^2/25 + (y - 2)^2/25=1 circle ????
f) xy = 3 line or point ?????? 1 solutions
Answer 122446 by Fombitz(13828) on 2008-11-06 08:49:52 (Show Source):
|
Rational-functions/166029: can someone please help me with this problem:
Graph the rational funciton.
Pf(x) = x+4 / x-1 1 solutions
Answer 122346 by Fombitz(13828) on 2008-11-05 16:29:54 (Show Source):
You can put this solution on YOUR website!Let's look at the function first.

It is undefined at x=1 (because of division by zero).
.
.
.
As you approach x=1 from the left, the numerator is positive, the denominator is negative, f(x) goes to negative infinity.
.
.
.
As you approach x=1 from the right, the numerator is positive, the denominator is positive, f(x) goes to positive infinity.
.
.
.
As x grow large (negative or positive), the function looks like,

So there is a horizontal asymptote at y=1.
.
.
.
f(x) crosses the x-axis when f(x)=0

f(x) cross the x-axis when x=-4.
.
.
.
f(x) crosses the y-axis when x=0

f(x) crosses the y-axis when y=-4.
.
.
.
|
Rational-functions/166034: can someone please help with this:
Give the equation of the horizontal asymptote of the rational function.
g(x) = x-5 / x-1
a. x = 1
b. y = 0
c. y = 1
d. y = 5 1 solutions
Answer 122343 by Fombitz(13828) on 2008-11-05 16:16:17 (Show Source):
You can put this solution on YOUR website!As x becomes very large (positive or negative), the function looks like,

.
.
.
Graphical proof of the asymptote, showing the discontinuity at x=1.
|
Quadratic_Equations/165943: Here are 3 equations that I need you to check my answers on:
#1) Solve this equation in qudratic form:
y^4 + 5y^2 - 36 = 0
y^2 + 5y - 36 = 0
(y + 9)(y-4)
y +9 = 0 y-4=9
y = -9 y = 4
y^2 = -9 y^2 = 4
sqr. rt. of y^2 = +/- sqr. rt. of 9 sqr. rt. of y^2 = +/- sqr. rt. of 4
y = =/- 9i y = +/- 2
solutions are 9i, -9i, 2, -2
#2) Solve a radical equation this is reducible to a quadratic equation
sqr. rt. of x-4 + x = 6
sqr. rt. of x-4 = 6-x
(sqr. rt. of x-4)^2 = (6-x)^2
x-4 = (6-x)^2
x-4 = 36 - 6x - 6x = X^2
x-4 = x^2 - 12x + 36
0 = x^2 - 13x + 40
0 = (x-5) (x - 8)
x = 5 x = 8
5 is a solution, 8 is not.
#3) Solve a fractional equation that is reducible to a quadratic equation:
2/y+1 + 1/y-1 = 1
(y+1) (y-1) (2/y+1 + 1/y-1) = 1(y+1)(y-1)
2(y^2-1) (y+1)(y-1) + (y+1)(y-1)
Here I am stuck on this. Please help. Thanks.
1 solutions
Answer 122299 by Fombitz(13828) on 2008-11-05 09:19:23 (Show Source):
You can put this solution on YOUR website!#1) Almost,

.
.
.
#2) Correct
.
.
.
#3)You're on the right track.
Distribute on the left hand side.

You can factor out a y but before you do that remember that y=0 is a solution.

Check the answer.

True.

True.
y=0, y=3.
|
Numbers_Word_Problems/165797: The population of Gondor is 3020 and is dropping by 12 people per year. The population of Shire is 824 and is increasing by 5 hobbits per year. How long until Gondor and Shire have the same population? 1 solutions
Answer 122213 by Fombitz(13828) on 2008-11-04 16:21:01 (Show Source):
You can put this solution on YOUR website!"Gondor is 3020 and is dropping by 12 people per year"

"Shire is 824 and is increasing by 5 hobbits per year"

Set the two populations equal to each other and solve for Y.

.
.
.
It's not an exact year, around the second month in the 129th year.
Around then, each village will have 1470 inhabitants.
|
Evaluation_Word_Problems/165788: Hello, I'm trying to help my 5th grader with a word problem, it's below, will much appreciate it , if you would help, got your site from google. This problem is due tom. morning.Thank you
Ivan, Zoe, Denys and Ethan wanted to divided up a big old pickle 30 feet long.
Denys wants twice as much as Ivan does. Zoe wants twice as much as Denys does, but half as much as Ethan does.
How should they divide the pickle?
1 solutions
Answer 122212 by Fombitz(13828) on 2008-11-04 16:08:53 (Show Source):
You can put this solution on YOUR website!Let's name everyone's cut length after the first letter of their name.
All their lengths together equal 30.
1. 
"Denys wants twice as much as Ivan does"
2. 
"Zoe wants twice as much as Denys does"
3. 
"Zoe wants half as much as Ethan does"
4. 
.
.
.
Since 3 and 4 both equal Z, set them equal to each other,

5. 
.
.
.
Now you can form an equation with only "I" as the variable, using substitutions from equations 2,3,and 5.
1.

.
.
.
Now go back and substitute this value in each of the equations,
2. 
3. 
5. 
.
.
.
Ivan gets 2 feet, Zoe gets 8 feet, Denys gets 4 feet and Ethan gets 16 feet.
|
Quadratic-relations-and-conic-sections/165719: This question is from textbook College Algebra
What are the steps to the following problem,
Instructions: "Write an equation for each ellipse"
Problem: minor axis with length 4: foci at (-5,0),(5,0)
Please Help I cannot seem to figure this one out.
Thank You
1 solutions
Answer 122167 by Fombitz(13828) on 2008-11-04 10:25:21 (Show Source):
You can put this solution on YOUR website!We have to work backwards from given information to find the major axis length (a) using minor axis length (b) and foci (c).
The general equation for an ellipse centered at (h,k) is given by,

.
.
.
Foci for an ellipse are located at 
where  .
The length of the minor axis is

Since the foci are symmetric about the y-axis, the ellipse is centered at (0,0).
The equation then becomes,
|
Expressions-with-variables/164667: Can someone help with this:
Use synthetic division to find the quotient and remainder(4x^3-6x+5)/(x-3)?
Thank you. 1 solutions
Answer 122165 by Fombitz(13828) on 2008-11-04 10:13:17 (Show Source):
You can put this solution on YOUR website!Showing synthetic division is a little difficult.
The first part will show the factor (left hand column), then the factor times the divisor,
then the next line will show the subtraction.
Repeat.
Hopefully it makes sense.
.
.
.
..........._______________
(x-3)|4x^3+0x^2-6x+5
4x^2:.4x^3-12x^2
.......................12x^2-6x+5
12x:...............12x^2-36x
...................................30x+5
30:.............................30x-90
............................................95
|
Age_Word_Problems/146358: Write an equation which models how old, in years, you will be when you are 3 times as old as the younger person.
Age now (mother) = 35
Younger person (daughter) age now = 14
age difference = 21 years
mother = X + 21
daughter = X
I was thinking it should be 3x + 21 = 3X.
It's not coming out right. Please help. 1 solutions
Answer 122158 by Fombitz(13828) on 2008-11-04 09:38:54 (Show Source):
You can put this solution on YOUR website!Mother = M = 35
Daughter = D = 14
In x years, the mother will be,

In x years, the daughter will be,

When will the mother be 3 times the daughters age?

3 1/2 years ago, the mother was 3 times the daughter's age.
The mother was 31 1/2 years old.
The daughter was 10 1/2 years old.
Are you sure the mother and daughter ages are correct??
|
Distributive-associative-commutative-properties/165710: Is there any reason why my question is going ignored.
I am trying to figure out how to solve this problem and have submitted it three times, still no answer
1/2 divided by 3/8+5*(1/3)
so, i am assuming the problem should written out like this:
1/2/3/8+5+(1/3) 1 solutions
Answer 122155 by Fombitz(13828) on 2008-11-04 09:19:07 (Show Source):
|
Quadratic_Equations/165538: how do i factor a quadratic equation and apply the zero product rule to find the solution set? 1 solutions
Answer 122051 by Fombitz(13828) on 2008-11-03 16:36:59 (Show Source):
You can put this solution on YOUR website!Here's an example.

You can factor the quadratic equation.

Zero product rule says either the first factor or the second factor could equal zero so solve for both.
.
.
.
First factor:

Second factor:

.
.
.
The solution set (zeros) for the equation are x=-1,-2.
You can check the answers by plugging into the equation or you could graph the equation to verify.

.
.
.
|
Vectors/165567: find a unit vector along each of the following vectors;
(i) r=3i^+4j^ (ii)r=12i^-5j^ (iii)r=-2i^-2j^-5k^ (iv)r=i^+2j^+3k^ 1 solutions
Answer 122049 by Fombitz(13828) on 2008-11-03 16:26:45 (Show Source):
You can put this solution on YOUR website!To find the unit vector in the direction of the given vector, divide the vector by its magnitude,M.
This way it has the same direction and magnitude of 1.
.
.
.
i)

.
.
.
ii)
 .
.
.
iii)

.
.
.
iv)
|
Probability-and-statistics/165391: find the percent of the total area under the standard curve between the given z-scores. z = 2.18 and z = 3.45 1 solutions
Answer 121984 by Fombitz(13828) on 2008-11-03 09:29:44 (Show Source):
You can put this solution on YOUR website!We can find the area under the curve from  to  and also from  to  , subtract them and that will give us the area between  and  . We then multiply by 100 to get the percentage. I used EXCEL's NORMSDIST function with the given z scores to calculate areas.
.
.
.

.
.
.
1.43% of the curve's area is between z=2.18 and z=3.45.
|
Linear_Algebra/165494: the problem:
Prove that (1,0,0,1) and (0,1,1,0) are linearly independent. I think they are dependent, am i missing something? 1 solutions
Answer 121980 by Fombitz(13828) on 2008-11-03 09:15:46 (Show Source):
You can put this solution on YOUR website!The previous discussion regarding dot product was not correct.
I mixed up orthogonality and linear independence.
.
.
.
For these two vectors to be linearly independent, then a combination of these two vectors with two scalar multipliers can only be zero when the multipliers are zero.
(1,0,0,1)A+(0,1,1,0)B=(0,0,0,0) only if A=B=0.
.
.
.
Look at each individual component of the vectors.
1.(1)A+(0)B=0
2.(0)A+(1)B=0
3.(0)A+(1)B=0
4.(1)A+(0)B=0
.
.
.
From 1 and 4,
A=0
From 2 and 3,
B=0
.
.
.
Therefore, you proved that they are linearly independent because the combination of the two vectors can only equal the zero vector when A=B=0.
Sorry for the confusion.
|
|