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Rational-functions/295503: Graph the rational funxtion f(x)=x^2+5x-6/x^2+2x-3. indentify the vertical and horizontal asymptotes, and any holes in the graph 1 solutions
Answer 213103 by Fombitz(13828) on 2010-04-23 09:51:05 (Show Source):
You can put this solution on YOUR website!Simplify first.
You can factor numerator and denominator and get rid of common factors, if there are any.

Vertical asymptotes occur when the denominator goes to zero.
For f(x), the denominator goes to zero when,

To find horizontal asymptotes, divide numerator and denominator by the highest exponent x term, then take the limit.

in the limit, the crossed out terms go to zero.

So then

There is a horizontal asymptote at  .
.
.
.
Since there is a division by zero at  , the value of  is undefined.
.
.
.
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Sequences-and-series/295547: I'm doing series and sequences, and I'm having an issue with this problem:
"Write the next term in the sequence. Then write a rule for the nth term."
-5, 10, -15, 20,...
I figured out that the next term in the sequence is -25, but I can't figure out a rule to explain it. We've tried everything that comes to mind, and the problem seems so simple but it feels as though something is just beyond my grasp. 1 solutions
Answer 212995 by Fombitz(13828) on 2010-04-22 22:37:15 (Show Source):
You can put this solution on YOUR website!Alternating signs with multiples of 5.
To get alternating signs,

To get powers of 5,

Now put it all together.

.
.
.Let's check.

.
.
.
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absolute-value/295391: I understand the absolute-value notation are in bars, not parentheses or brackets. I also understand if there is a negative number in the bars, the absolute value becomes a positive number......
the question is:
The absolute value of negative seven is less than or equal to seven.
choices:
a. | –7 | = 7
b. | –7 | < 7
c. | –7 | ≤ 7
d. | –7 | ≥ 7
I choose a and so did the teacher. Other students questioned her about it and now she is saying a is the wrong answer.
I choose a because the question asked the absolute value of -7, | –7 | is less than or = to 7. Since the absolute value of -7 is 7 it cannot be less than...because they are equal.
this is how I understand...please correct me if i'm wrong.
if a isn't the correct answer, then none of the choices she gave would be right.
b. | –7 | < 7 ~ the absolute value of -7 is 7 . 7 cant be less than 7 because 7=7
c. | –7 | ≤ 7 ~ the absolute value of -7 is 7. 7 does = 7 but is it not less than 7
d. | –7 | ≥ 7 ~ the absolute value of -7 is 7. 7 does = 7 but is it not greater than 7
THANKS!! 1 solutions
Answer 212874 by Fombitz(13828) on 2010-04-22 16:31:45 (Show Source):
You can put this solution on YOUR website!I think the key is in the word "or"
"less than or equal to" includes equal as does
"greater than or equal to"
The correct answers would be a,c, and d.
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Mixture_Word_Problems/295319: A metallurgist has one alloy containing 40% aluminum and another contained 57% aluminum. How many pounds of each alloy must he use to make 54 pounds containing 51% aluminum. 1 solutions
Answer 212868 by Fombitz(13828) on 2010-04-22 15:35:15 (Show Source):
You can put this solution on YOUR website!Let A be the number of pounds of 40% aluminum, B be the number of pounds of 57% aluminum.
1. 
2. 
Use eq. 1,

Substitue into eq. 2,

Then from eq.1,

.
.
.
Use  (or about  lbs) of 40% alloy and  (or about  lbs) of 57% alloy to get  lbs of 51% aluminum.
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Graphs/295155: Find the intercepts, asymptotes, use limits to describe the behavior at the vertical asymptotes and analyze and draw the graph of f(x)=(x+1)/(x^2-3x-10) 1 solutions
Answer 212786 by Fombitz(13828) on 2010-04-22 09:07:10 (Show Source):
You can put this solution on YOUR website!To find the y-intercept, set x=0 and solve for y.

(0,-1/10)
To find the x-intercept, set y=0 and solve for x.

(-1,0)
To find vertical asymptotes, look for x where the denominator goes to zero.

Two solutions:

.
.
.

To find horizontal asymptotes, divide all terms by the highest order of x.

Now take the limit as x goes to  .
So there is a horizontal asymptote at y=0.
.
.
.
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logarithm/295210: Please help me with solving a single logarithm of log(t+)+log(6) 1 solutions
Answer 212781 by Fombitz(13828) on 2010-04-22 08:54:17 (Show Source):
You can put this solution on YOUR website!I think you've left out part of your first log argument.
To make into a single logarithm, follow the log rule,

So in your case,

where Z is the missing part of your argument.
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absolute-value/294858: x(|x-2|)>=0. x-2 is an absolute value.
I thought the answer was x= all real numbers, but the x on the outside of the bracket messes that up. How do I approach this? 1 solutions
Answer 212603 by Fombitz(13828) on 2010-04-21 16:52:20 (Show Source):
You can put this solution on YOUR website!Absolute value problems are really two problems in one.
Positive solution (where  ):

This is true when  and also when 
.
.
.
Negative solution (where  ):

Break up the region into three regions,

and test a point to check the inequality
 ,

No, not in the valid region.
.
.
.
 ,

Yes, in the valid region.
.
.
.
 ,

No, not in the valid region.
So from the negative solution, the valid region would be (0,2).
Put together with  and  , then the valid region is,
(  )
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