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Functions/594275: If a ball is dropped from the top of a 256-ft building, then the formula
h(t)= 256-16t^2
expresses its height h(t) in feet as a function of the time t in seconds.
1.Find h(2), the height of the ball 2 seconds after it is dropped.
2.Find h(4).
1 solutions
Answer 376672 by Alan3354(30924) on 2012-04-01 21:57:03 (Show Source):
You can put this solution on YOUR website!If a ball is dropped from the top of a 256-ft building, then the formula
h(t)= 256-16t^2 expresses its height h(t) in feet as a function of the time t in seconds.
1.Find h(2), the height of the ball 2 seconds after it is dropped.
Sub 2 for t
h(2) = 256 - 16*2^2 = 256 - 64
h(2) = 192 ft
------
2.Find h(4).
Do the same as above.
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Exponents-negative-and-fractional/594120: supposed to be this, keeps putting my fractional powers in the wrong space: 2x^(-7/4)/4x^(4/3)
I have been stuck trying to work this out all day, it says the answer is:
or x^(11/12)/2x^4
I can't seem to get it to this, have been trying to use the rule:

or moving the negative exponent down and applying the:
But with no success. :( please give me all the steps in the answer, many thanks Jim. 1 solutions
Answer 376623 by Alan3354(30924) on 2012-04-01 16:37:30 (Show Source):
You can put this solution on YOUR website! supposed to be this, keeps putting my fractional powers in the wrong space: 2x^(-7/4)/4x^(4/3)
------------------
= x^(-7/4)/2x^(4/3)
Multiply NUM and DEN by x^(7/4)
= 1/2x^(4/3 + 7/4)
= 1/2x^(37/12)
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Multiply NUM and DEN by x^(11/12) to eliminate fractional exponents in the DEN.
= x^(11/2)/2x^4
------------------
I have been stuck trying to work this out all day, it says the answer is:
 or x^(11/12)/2x^4
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Linear-systems/594111: How do you solve for x and y in this problem. 5x + 2y = 63 and 3x + 2y = 51 1 solutions
Answer 376618 by Alan3354(30924) on 2012-04-01 16:24:06 (Show Source):
You can put this solution on YOUR website!How do you solve for x and y in this problem. 5x + 2y = 63 and 3x + 2y = 51
----------
There's more than 1 way, but
You can subtract one equation from the other and eliminate the y terms.
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Travel_Word_Problems/594029: Elda walked from her home to her friend Niabi's house at 4.5 km/hr. When Elda returned home along the same route, she strolled at 3.5 km/hr. Elda took a total of 40 min to walk to Niabi's house and back again.
a) How many minutes did Elda take to walk from her home to Niabi's house?
b) How far is it from Elda's home to Niabi's house? 1 solutions
Answer 376581 by Alan3354(30924) on 2012-04-01 12:15:24 (Show Source):
You can put this solution on YOUR website!Elda walked from her home to her friend Niabi's house at 4.5 km/hr. When Elda returned home along the same route, she strolled at 3.5 km/hr. Elda took a total of 40 min to walk to Niabi's house and back again.
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Avg speed for the round trip = 2*4.5*3.5/(4.5 + 3.5)
= 31.5/8 km/hr
RT distance = r*t = 31.5/8 * (2/3) hr = 21/8 km
--> 21/16 km each way.
--------------------------
a) How many minutes did Elda take to walk from her home to Niabi's house?
t = d/r = (21/16)/4.5 = 21/72 hours
= 7/24 hours
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b) How far is it from Elda's home to Niabi's house?
--> 21/16 km each way.
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Quadratic_Equations/593997: a rocket is launched from an 18-foot cliff with an initial velocity of 80 feet per second. the height above the ground of the rocket t seconds after launch is given by the equation h= -16^2+80t+18. hjow long after the rocket is launched will it hit the ground? round your answer to the nearest tenth. 1 solutions
Answer 376580 by Alan3354(30924) on 2012-04-01 12:10:56 (Show Source):
You can put this solution on YOUR website!a rocket is launched from an 18-foot cliff with an initial velocity of 80 feet per second. the height above the ground of the rocket t seconds after launch is given by the equation h= -16^2+80t+18. hjow long after the rocket is launched will it hit the ground? round your answer to the nearest tenth.
-------------
It's when h = 0.
h= -16^2+80t+18 = 0
Solve for t.
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Why is this called a rocket? It has no engine, doesn't accelerate.
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Miscellaneous_Word_Problems/593985: When a screen is placed 3 metres from a projector, the picture occupies 3 square
metres. How large will the picture be when the projector is 5 metres from the
screen?
I have no idea what the answer would be. 5 seems too easy...Maybe they didn't give enough info?
1 solutions
Answer 376575 by Alan3354(30924) on 2012-04-01 11:00:17 (Show Source):
You can put this solution on YOUR website!When a screen is placed 3 metres from a projector, the picture occupies 3 square
metres. How large will the picture be when the projector is 5 metres from the
screen?
------------------
Both sides of the picture will be 5/3 as big.
3*(5/3)*(5/3) = 75/9
= 25/3 sq meters
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Linear_Algebra/593991: Use the elimination method to solve the following system of equations
4x – 2y – z = –5
x – 3y + 2z = 3
3x + y – 2z = –5 1 solutions
Answer 376569 by Alan3354(30924) on 2012-04-01 09:46:27 (Show Source):
You can put this solution on YOUR website!Use the elimination method to solve the following system of equations
4x – 2y – z = –5
x – 3y + 2z = 3
3x + y – 2z = –5
-------------------
Multiply the 1st eqn by 2, then eliminate the z terms.
Then it's only x & y.
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Quadratic_Equations/593994: Help! I find myself getting confused when working with negative numbers. Can someone help with this problem and also explain it as well. Thanks so much!
Write a quadratic equation in the variable x having the given numbers as solutions. Write the equation in standard form, ax^2+bx+c=0. The solutions are; -11,7. 1 solutions
Answer 376567 by Alan3354(30924) on 2012-04-01 09:44:56 (Show Source):
You can put this solution on YOUR website!Write a quadratic equation in the variable x having the given numbers as solutions. Write the equation in standard form, ax^2+bx+c=0. The solutions are; -11,7.
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(x - (-11))*(x - 7) = 0
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Points-lines-and-rays/593992: This is the question that I am having difficulty with.
Write the standard form of the equation from the line that passes through points (-6,-8) and (-4,-11).
I have found the slope = -3/2 and I can get through the next step in slope intercept form y=-3/2x -17 but then I get stuck. HELP!!! 1 solutions
Answer 376566 by Alan3354(30924) on 2012-04-01 09:39:13 (Show Source):
You can put this solution on YOUR website!Write the standard form of the equation from the line that passes through points (-6,-8) and (-4,-11).
I have found the slope = -3/2
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Use y = mx + b and either point to find b, the y-intercept
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-8 = (-3/2)*(-6) + b
b = -17
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The eqn is y = (-3/2)x - 17
3x + 2y = -34 in standard form
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Quadratic_Equations/593595: If a stone is tossed from the top of a 230 meter building, the height of the stone as a function of time is given by h(t) = -9.8t^2 – 10t + 230, where t is in seconds, and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredth’s place; include units in your answer. 1 solutions
Answer 376563 by Alan3354(30924) on 2012-04-01 08:47:31 (Show Source):
You can put this solution on YOUR website!If a stone is tossed from the top of a 230 meter building, the height of the stone as a function of time is given by h(t) = -9.8t^2 – 10t + 230, where t is in seconds, and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredth’s place; include units in your answer.
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The other tutor got the right answer, ~ 4.36 seconds, but
if you're on Earth, the equation is
h(t) = -4.9t^2 – 10t + 230
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Polygons/593823: How to find the area of a regular polygon, it is a triangle with side measuring 6 inches? 1 solutions
Answer 376477 by Alan3354(30924) on 2012-03-31 12:40:03 (Show Source):
You can put this solution on YOUR website!How to find the area of a regular polygon, it is a triangle with side measuring 6 inches?
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Given the side length, for any regular polygon
 n = # of sides, s = side length
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Geometry_Word_Problems/593806: Please help and show me if I am doing this right! I have to solve an quadratic formula: 3x^=19x-14=0
Ax^+bx+c=0, a=0
x=(-b±√(b^2-4ac))/2a
3x^+19x-14=0
A=3
B=19
C=14
3^=(-19±√(〖-19〗^2-4(3)(14)))/(2(3))
3^= (19±√(〖361〗^+ 168))/6
3^= (19±√529)/6
19+23=42=7
6 6
my answer is 7 over 6.
1 solutions
Answer 376461 by Alan3354(30924) on 2012-03-31 10:17:20 (Show Source):
You can put this solution on YOUR website!Please help and show me if I am doing this right! I have to solve an quadratic formula: 3x^=19x-14=0
Ax^+bx+c=0, a=0
x=(-b±√(b^2-4ac))/2a
3x^+19x-14=0
A=3
B=19
C=14 *********** C = -14
3^=(-19±√(〖-19〗^2-4(3)(14)))/(2(3)) ???? 3^ = ???? It's x =
3^= (19±√(〖361〗^+ 168))/6 ************ You changed signs again, got it right.
3^= (19±√529)/6
19+23=42=7
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(-19+23)/6 = 4/6
x = 2/3
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(-19-23)/6 = -42/6
x = -7
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6 6
my answer is 7 over 6.
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You were close.
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| Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=529 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: 0.666666666666667, -7.
Here's your graph:
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Linear-systems/593805: Can someone help me with this .also i need clarification when doing Elimination. how do i know when to add and subtract can i have 2 examples of showing when to add also and can someone help me with these 2 equations.I am trying to practice for exams.
4(2x-y=-2
2(4x+y=24
8x-12y=-2
- 8x+2y=48
- __________
- -10y +-50
- Y=-50/-10
- Y-5
4x+y=24
4x+5=24
4x=24-5
4x=19
.....this isn’t looking right so far
Also
Y=x+3
Y=x^2
1 solutions
Answer 376460 by Alan3354(30924) on 2012-03-31 10:07:52 (Show Source):
You can put this solution on YOUR website!Can someone help me with this .also i need clarification when doing Elimination. how do i know when to add and subtract can i have 2 examples of showing when to add also and can someone help me with these 2 equations.I am trying to practice for exams.
4(2x-y=-2
2(4x+y=24
8x-12y=-2 *** Is this a different problem? Where did you get -12y ?
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4(2x-y=-2
2(4x+y=24
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2x-y=-2
4x+y=24
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6x = 22
x = 11/3
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2x-y=-2
y = 2x + 2
y = 28/3
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- 8x+2y=48
- __________
- -10y +-50
- Y=-50/-10
- Y-5
4x+y=24
4x+5=24
4x=24-5
4x=19
.....this isn’t looking right so far
Also
Y=x+3
Y=x^2
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Both equal y, so
x + 3 = x^2
| Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=13 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: 2.30277563773199, -1.30277563773199.
Here's your graph:
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y = x + 3
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Trigonometry-basics/593773: Factor completely: 12a^2b + 30a^b2.
I'm not even sure were to begin. 1 solutions
Answer 376459 by Alan3354(30924) on 2012-03-31 09:56:50 (Show Source):
You can put this solution on YOUR website!Factor completely: 12a^2b + 30a^b2.
I'm not even sure were to begin.
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Both coefficients are even numbers. Begin with that.
Both terms have an a.
Both terms have a b.
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Factor things out. Then divide by other factors.
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Systems-of-equations/593742: Molly has a solar panel with a width of 26in. To get the proper inclination for her climate, she needs a right triangular support frame that has one leg twice as long as the other. To the nearest thenth of an inch, what dimensions should the frame have?
so right triangle a^2+b^2=c^2
2x^2+x^2=26^2
3x^2=676
(3x^2=676)/3
x^2=225
square root the whole thing
x=15 but when i check my work it doesn't add up so i know i must be doing it wrong 1 solutions
Answer 376437 by Alan3354(30924) on 2012-03-30 22:39:55 (Show Source):
You can put this solution on YOUR website!Molly has a solar panel with a width of 26in. To get the proper inclination for her climate, she needs a right triangular support frame that has one leg twice as long as the other. To the nearest thenth of an inch, what dimensions should the frame have?
so right triangle a^2+b^2=c^2
2x^2+x^2=26^2 ***************** (2x)^2 + x^2 = 26^2
3x^2=676 ************************ 5x^2 = 676
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Exponents/593727: use the product rule for exponents to simplify the expression, write the answer in exponential form. 5^8+5^4 1 solutions
Answer 376424 by Alan3354(30924) on 2012-03-30 20:42:09 (Show Source):
You can put this solution on YOUR website!use the product rule for exponents to simplify the expression, write the answer in exponential form.
5^8+5^4
= 
Is that simpler?
= 625*626
How about that?
= 391250
That's simple.
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