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Assume that all expressions under radicals represent positive numbers.
The three should be on the radical, I just couldn't figure out how to get it on there.
1 solutions
Answer 205597 by Alan3354(30993)   on 2010-03-20 18:44:25 (Show Source):
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test/283016: Can somebody help me solve this problem?
Solve: x-2/5 x y=-2
3x+2y = 0
solve for x and y.
1 solutions
Answer 205585 by Alan3354(30993) on 2010-03-20 16:50:16 (Show Source):
You can put this solution on YOUR website!Can somebody help me solve this problem?
Solve: x-2/5 x y=-2
3x+2y = 0
solve for x and y.
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Is there an xy term?
x - (2/5xy) = -2 or
(x-2)/5xy = -2 ?
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Proportions/283145: The weight of body varies inversely with the square of the square of its distance from the center of earth. Assuming that the radius of earth is 3960miles how much would a man weigh at an altitude of 1 mile above the earths surface?
1 solutions
Answer 205577 by Alan3354(30993) on 2010-03-20 16:15:18 (Show Source):
You can put this solution on YOUR website!The weight of body varies inversely with the square of the square of its distance from the center of earth. Assuming that the radius of earth is 3960miles how much would a man weigh at an altitude of 1 mile above the earths surface?
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Different men weigh different amounts.
If he weighs W on the surface (3960 miles from the CG), his weight 1 mile above the surface will be
=~ 0.999495W
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Linear-equations/283156: A car goes 30 miles per hour on a 1 mile track and on his second lap he wants his average speed to be 60 miles per hour. What is his speed on the second lap?(teacher said not 90 miles per hour)
1 solutions
Answer 205573 by Alan3354(30993) on 2010-03-20 16:07:13 (Show Source):
You can put this solution on YOUR website!A car goes 30 miles per hour on a 1 mile track and on his second lap he wants his average speed to be 60 miles per hour. What is his speed on the second lap?(teacher said not 90 miles per hour)
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It's not 90.
The 2nd lap at 90 mph will take 40 seconds. That's 2 miles in 2 2/3 minutes,
--> an overall average of 45 mph
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You might think that since he made the 1st lap 1/2 of 60 mph, he could do the 2nd at 2x 60 mph to average 60 mph overall.
The 2nd lap at 120 mph would take 30 seconds.
The total time for 2 miles would be 2.5 minutes, --> 48 mph for the 2 miles.
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1 mile at 30 mph takes 2 minutes.
2 miles at 60 mph also takes 2 minutes, so time is up - it's not possible to average 60 mph for the 2 laps from that point.
It's what is called a "trick question", the answer is surprising.
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However, the problem says, "on his second lap he wants his average speed to be 60 miles per hour" It doesn't say 60 mph overall.
To average 60 mph on the 2nd lap, he'd go 60 mph.
The wording is careless and ambiguous.
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Expressions-with-variables/283172: Find the equation of the line that passes through point (4,7) and that is perpendicular to the line whose equation is y = -2x + 1.
1 solutions
Answer 205565 by Alan3354(30993) on 2010-03-20 15:36:54 (Show Source):
You can put this solution on YOUR website! Given 2 points example.
Find the equation of the line thru the points (2,1) and (3,5)
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This is a 2 step process. First find the slope of the line thru the points.
slope, m = diffy/diffx
m = (5-1)/(3-2)
m = 4
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Now use y = mx + b with either point to find b, the y-intercept.
y = mx + b
5 = 4*3 + b
b = -7
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y = mx + b
y = 4x - 7 is the answer.
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For further assistance, or to check your work, email me via the thank you note.
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A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
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Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 13
The slope, m = -3
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The slope of lines parallel have the same slope.
The slope of lines perpendicular is the negative inverse, m = +1/3
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Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
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For further assistance, or to check your work, email me via the thank you note.
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Graphs/283112: Find the distance between each pair of points and the midpoint of the line segment joining the points. Leave distance n radical form.
(-5,4), (6,-1)
1 solutions
Answer 205546 by Alan3354(30993) on 2010-03-20 12:32:45 (Show Source):
You can put this solution on YOUR website!Find the distance between each pair of points and the midpoint of the line segment joining the points. Leave distance n radical form.
(-5,4), (6,-1)
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To find the midpoint, get the averages of x and y separately.
x = (-5+6)/2 = 1/2
y = (4-1)/2 = 3/2
Midpoint is (1/2,3/2)
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Rational-functions/279410: Given Function and one of its zeros, find all of the zeros of the function.
h(x)=
1 solutions
Answer 205534 by Alan3354(30993) on 2010-03-20 11:42:37 (Show Source):
You can put this solution on YOUR website!Given Function and one of its zeros, find all of the zeros of the function.
h(x)=
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20 has factors of 1, 2, 4, and 5 to consider
Because of the 11x, it has to be an even number, so 1 and 5 are out.
Try 2 and 4, plus and minus
h(2) = not zero
h(4) is too big
h(-4) = 0 That's one.
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Divide by (x+4)
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| Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
The discriminant -4 is less than zero. That means that there are no solutions among real numbers.
If you are a student of advanced school algebra and are aware about imaginary numbers, read on.
In the field of imaginary numbers, the square root of -4 is + or -  .
The solution is  , or
Here's your graph:
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x = 2 ± i
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Linear-equations/283025: I am suffering with this, can u plkease help me:
y=-2/3x-1
need to graph it on a y -20 an 20 and x-20 and 20 graph
need to find the y inercept ordered pair
1 solutions
Answer 205519 by Alan3354(30993) on 2010-03-20 09:45:30 (Show Source):
You can put this solution on YOUR website!It's a straight line, so you need 2 points.
Pick values of x and find y.
x....y
0....-1 --> (0,-1) the y-intercept
9....-7 --> (9,-7)
Draw a line thru the points
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Linear-equations/282929: find the equation of the line that is normal to the line 2x-y= -5 and passes through the point (2,7) write the equation in standard form.
1 solutions
Answer 205423 by Alan3354(30993) on 2010-03-19 18:39:57 (Show Source):
You can put this solution on YOUR website! Given 2 points example.
Find the equation of the line thru the points (2,1) and (3,5)
---------------------
This is a 2 step process. First find the slope of the line thru the points.
slope, m = diffy/diffx
m = (5-1)/(3-2)
m = 4
---------
Now use y = mx + b with either point to find b, the y-intercept.
y = mx + b
5 = 4*3 + b
b = -7
-------
y = mx + b
y = 4x - 7 is the answer.
------------------------
For further assistance, or to check your work, email me via the thank you note.
----------------------
A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
-----------------
Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 13
The slope, m = -3
------------------
The slope of lines parallel have the same slope.
The slope of lines perpendicular is the negative inverse, m = +1/3
----------------
Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
------------------------
For further assistance, or to check your work, email me via the thank you note.
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Functions/282873: Hello,
This question is from our online homework.
The domain of the function
x+10
-----
x^2-1
Write the answer in interval notation.
I know that x cannot =1 or the denominator would = 0, I am pretty sure it is a multi-part answer needing the U symbol, but no matter how I enter it I get an incorrect answer. I know when you have infinity you always use (or). I may be confused on when to use [ and ].
Any help would be greatly appreciated.
Thanks!
1 solutions
Answer 205380 by Alan3354(30993) on 2010-03-19 14:59:15 (Show Source):
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Travel_Word_Problems/282902: My professor says there is "an unacceptable answer" and I needed more detail on line 7 of the equation. I am lost. Please help. Here's the original question:
Frank drove 300 miles to the beach for vacation. On the way home, he averaged 10 miles per hour less, and the drive took him one hour longer. What was his total driving time?
D=rt
r= time on the way to the beach
r-10= time returning
t=time on the way to the beach
t+1=return time
r*t=300
(r-10)*(t+1)=300 "You need more detail here."
r=60
t=5
return= 5+1
11 hours total driving time
1 solutions
Answer 205369 by Alan3354(30993) on 2010-03-19 14:50:44 (Show Source):
You can put this solution on YOUR website!r*t=300
(r-10)*(t+1)=300 "You need more detail here."
r=60
t=5
return= 5+1
11 hours total driving time
--------------------
Maybe he means from there onward ??
r*t=300
(r-10)*(t+1)=300
-------------------
How did you go from there to
r=60
t=5 ??
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Linear-equations/282903: Find the equation of the line containing the point (1,2) with slope 3.
1 solutions
Answer 205367 by Alan3354(30993) on 2010-03-19 14:47:03 (Show Source):
You can put this solution on YOUR website! Given 2 points example.
Find the equation of the line thru the points (2,1) and (3,5)
---------------------
This is a 2 step process. First find the slope of the line thru the points.
slope, m = diffy/diffx
m = (5-1)/(3-2)
m = 4
---------
Now use y = mx + b with either point to find b, the y-intercept.
y = mx + b
5 = 4*3 + b
b = -7
-------
y = mx + b
y = 4x - 7 is the answer.
------------------------
For further assistance, or to check your work, email me via the thank you note.
----------------------
A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
-----------------
Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 13
The slope, m = -3
------------------
The slope of lines parallel have the same slope.
The slope of lines perpendicular is the negative inverse, m = +1/3
----------------
Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
------------------------
For further assistance, or to check your work, email me via the thank you note.
|
Linear-equations/282904: Find the equation of the line containing the point (2,7) and parallel to the line 2x-y=-1
1 solutions
Answer 205366 by Alan3354(30993) on 2010-03-19 14:46:08 (Show Source):
You can put this solution on YOUR website!Here are examples:
Given 2 points example.
Find the equation of the line thru the points (2,1) and (3,5)
---------------------
This is a 2 step process. First find the slope of the line thru the points.
slope, m = diffy/diffx
m = (5-1)/(3-2)
m = 4
---------
Now use y = mx + b with either point to find b, the y-intercept.
y = mx + b
5 = 4*3 + b
b = -7
-------
y = mx + b
y = 4x - 7 is the answer.
------------------------
For further assistance, or to check your work, email me via the thank you note.
----------------------
A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
-----------------
Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 13
The slope, m = -3
------------------
The slope of lines parallel have the same slope.
The slope of lines perpendicular is the negative inverse, m = +1/3
----------------
Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
------------------------
For further assistance, or to check your work, email me via the thank you note.
|
Probability-and-statistics/282899: I am having problems trying to figure this problem. I am not sure if I have to multiply the diagonal meter by the lengths of the sides.
Problem:
One side of a rectangular stage is 2 meters longer than the other. If the diagonal is 10 meters, then what are the lengths of the sides?
1 solutions
Answer 205353 by Alan3354(30993) on 2010-03-19 14:17:40 (Show Source):
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Sequences-and-series/282813: Choose the recursive formula for the sequence 7, –1, –9, –17, ... Then choose the next term.
a. an= an - 1 – 7, where a1= 7; –24
b. an= an - 1 – 8, where a1= 7; –25
c. an= an - 1 – 7, where a1= –17; –25
d. an= an - 1 + 8, where a1= 7; –25
(n, n-1, and 1 are below the a but not sure how to write that here. I posted a pic here: http://i39.tinypic.com/33c0ocl.jpg)
1 solutions
Answer 205324 by Alan3354(30993) on 2010-03-19 11:13:12 (Show Source):
You can put this solution on YOUR website!Choose the recursive formula for the sequence 7, –1, –9, –17, ... Then choose the next term.
a. an= an - 1 – 7, where a1= 7; –24
b. an= an - 1 – 8, where a1= 7; –25
c. an= an - 1 – 7, where a1= –17; –25
d. an= an - 1 + 8, where a1= 7; –25
----------------------------------------
a.
a1 = 7
a2 = 0
a3 = -7 That doesn't fit.
---------------------------
c.
a1 = -17
a2 = -24
a3 = -31 That doesn't match
----------------------------
d.
a1 = 7
a2 = 15
a3 = 22 No match
-----------------------
b.
a1 = 7
a2 = -1
a3 = -9
a4 = -17
a5 = -25 I'd go with b.
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Graphs/282777: The number of ordered pair solutions (x, y) with real coordinates of the system
3x^2 − y^2 = 3
5x^2 − 2y^2 = 2
is
(A) 0 (B) 1 (C) 2 (D) 3 (E) 4
1 solutions
Answer 205319 by Alan3354(30993) on 2010-03-19 10:55:55 (Show Source):
You can put this solution on YOUR website!3x^2 − y^2 = 3
5x^2 − 2y^2 = 2
6x^2 - 2y^2 = 6 Eqn 1 times 2
--------------- Subtract
x^2 = 4
x = ± 2
-------
Sub for x into either eqn
--> y = ± 3
-------------
(-2,-3)
(-2,3)
(2,3)
(2,-3)
--> 4 intersections
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Pythagorean-theorem/282819: Finding the missing length of the right triangle of the formula a=48 and b=20 I understand you 48 to the second power and 20 to the second power, but not sure how the caulations was done to get c= 2304 + 400 so do you multiple, or what?
1 solutions
Answer 205311 by Alan3354(30993) on 2010-03-19 10:22:35 (Show Source):
You can put this solution on YOUR website!Finding the missing length of the right triangle of the formula a=48 and b=20 I understand you 48 to the second power and 20 to the second power, but not sure how the caulations was done to get c= 2304 + 400 so do you multiple, or what?
-----------------------
If 48 and 20 are the 2 short sides, then you add as you did then take the square root.
-------------------------
It's 
2304 + 400 = 2704
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Sequences-and-series/282814: Choose the explicit formula for the sequence 1, 1/4, 1/9, 1/16, ... Then find a15.
(15 is below a. Not sure how to type that here, so I posted a pic of the question and answers here: http://i44.tinypic.com/16lwyzn.jpg)
1 solutions
Answer 205308 by Alan3354(30993) on 2010-03-19 10:07:58 (Show Source):
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