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Surface-area/388011: Two solid spheres have surface areas 144 pi sq.cm and 256 pi sq.cm, respectively. They are melted and recast to form a larger sphere. Find the surface area of this sphere in sq.cm. 1 solutions
Answer 274396 by Alan3354(31487) on 2010-12-20 15:00:07 (Show Source):
You can put this solution on YOUR website!Two solid spheres have surface areas 144 pi sq.cm and 256 pi sq.cm, respectively. They are melted and recast to form a larger sphere. Find the surface area of this sphere in sq.cm.
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Find the radii, then the volumes.
Add the volumes, find the radius of the total.
Find the surface area of the total.
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for 144pi sq cm, r = 6
for 256pi sq cm, r = 8
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for r = 6, V = 288pi cc
for r = 8, V = 2048pi/3 cc
Total volume = 2912pi/3 cc
r =~ 8.996 cm
SA total =~ 1016.945 sq cm
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=~ 323.7pi sq cm, less the the sum of the 2 original areas
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Travel_Word_Problems/388062: the angles of elevation to an airplane from two points A and B on level ground are 51(degrees) and 68(degrees), respectively. The points A and B are 2.5 miles apart, and the airplane is east of both points in the same vertical plane. Find the altitude of plane. 1 solutions
Answer 274395 by Alan3354(31487) on 2010-12-20 14:49:31 (Show Source):
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Travel_Word_Problems/388066: the angles of elevation to an airplane from two points A and B on level ground are 51 degrees and 68 degrees respectively. The points A and B are 2.5 miles apart, and the airplane is east of both points in the same vertical plane. Find the altitude of the plane.
thanks for the help! i've been stuck on this problem for like an hour now! 1 solutions
Answer 274392 by Alan3354(31487) on 2010-12-20 14:41:29 (Show Source):
You can put this solution on YOUR website!the angles of elevation to an airplane from two points A and B on level ground are 51 degrees and 68 degrees respectively. The points A and B are 2.5 miles apart, and the airplane is east of both points in the same vertical plane. Find the altitude of the plane.
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The interior angle at point B is 180 - 68 = 112º
Angle C (at the plane) = 180 - (A+B) = 17º
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Use the Law of Sines to find side AC
AB/sin(17) = AC/sin(112)
AC = AB*sin(112)/sin(17) =~ 7.928 miles
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Altitude = AC*sin(51) =~ 6.163 miles
= 32532 feet
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Quadratic_Equations/388044: how many seconds will the ball be 75 ft haigh after hit 2 feet off the ground and initial upward velocity of 90 ft / sec.
75h = 2 ho + 90 t - 16 t squared 1 solutions
Answer 274383 by Alan3354(31487) on 2010-12-20 13:56:54 (Show Source):
You can put this solution on YOUR website! how many seconds will the ball be 75 ft haigh after hit 2 feet off the ground and initial upward velocity of 90 ft / sec.
75h = 2 ho + 90 t - 16 t squared
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h(t) = -16t^2 + 90t + 2
At h = 75:
-16t^2 + 90t + 2 = 75
-16t^2 + 90t - 73 = 0
| Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=3428 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: 0.982839853961944, 4.64216014603806.
Here's your graph:
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The ball passes 75 feet twice, ascending at t = 0.982839853961944, and descending at t = 4.64216014603806 seconds.
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The ball is exactly 75 feet high for zero time, or dt seconds.
It is at or above 75 feet for the difference between the 2 times above,
=~ 3.659 seconds
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Rate-of-work-word-problems/387936: An aquarium tank can hold 6000 liters of water. There are two pipes that can be used to fill the tank. The first pipe alone can fill the tank in 50 minutes. The second pipe can fill the tank in 75 minutes by itself. When both pipes are working together, how long does it take them to fill the tank? 1 solutions
Answer 274243 by Alan3354(31487) on 2010-12-19 21:12:07 (Show Source):
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Travel_Word_Problems/387938: A ball is thrown upward with an initial speed of 24.5 m/s. When is it 19.6m high?
1 solutions
Answer 274242 by Alan3354(31487) on 2010-12-19 21:10:34 (Show Source):
You can put this solution on YOUR website!You didn't specify the equation of motion, or the starting height.
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h(t) = -4.9t^2 + vt is commonly used, assuming h(0) = 0
h(t) = -4.9t^2 + 24.5t
-4.9t^2 + 24.5t = 19.6
t^2 - 5t + 4 = 0
(t-1)*(t-4) = 0
t = 1 second going up
t = 4 seconds descending
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Miscellaneous_Word_Problems/387884: Preform the indicated operation. Wright the answer in scientific notation.
( 6 x 10^-2)(5.67 x 10^3)
This is how I put this into the calculator and I got 385.344. I move the decimal over two places to get the answer 3.85 x 10^2. What happened to the .344?
I am studying for a test and I have the answers for the pre-test and I am allowed to use the calculator on the test. I t will help so much if I really knew how to use it. 1 solutions
Answer 274200 by Alan3354(31487) on 2010-12-19 17:11:17 (Show Source):
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Miscellaneous_Word_Problems/387874: John wants to fence a 150 square meters rectangular field. He wants the legnth and width to be natural numbers. What field dimension will require the least amount of fencing? 1 solutions
Answer 274199 by Alan3354(31487) on 2010-12-19 17:07:53 (Show Source):
You can put this solution on YOUR website!The length and width would be the factors of 150.
150 =
1 x 150
2 x 75
3 x 50
5 x 30
10 x 15
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10 by 15 is the smallest perimeter.
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Radicals/387827: How do I solve:
(5 sqrt10 + 7 sqrt5)(2 sqrt5 + sqrt10)
sorry but there is no square root button on the keyboard. I hope you can understand where the square roots are. Thank You. 1 solutions
Answer 274197 by Alan3354(31487) on 2010-12-19 17:04:13 (Show Source):
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Expressions-with-variables/387861: Can you help me with this question? If a bride and groom want to serve a nut mixture containing 25% nut peanuts, and the bride has available mixtures that are either 40% or 10% peanuts, how much of each type should be mixed to get 10lb that are 25% peanuts? Thank you! Shelly 1 solutions
Answer 274196 by Alan3354(31487) on 2010-12-19 17:00:59 (Show Source):
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Travel_Word_Problems/387691: A motorboat travels 441mi in 7 hours going upstream and 522mi in 6 hours going downstream. What is the rate of the boat in still water and what is the rate of the current? 1 solutions
Answer 274075 by Alan3354(31487) on 2010-12-18 21:54:45 (Show Source):
You can put this solution on YOUR website! A motorboat travels 441mi in 7 hours going upstream and 522mi in 6 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?
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441/7 = 63 mph
522/6 = 87 mph
The boat's speed is the average (63 + 87)/2 = 75 mph
The current is the difference 87 - 72 = 12 mph
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