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Linear-equations/394473: 1) write an equation in slope intercept form that passes through in parallel (2,-4) y=4x-6
2) write an equation in slope intercept form that passes through in perpendicular (-2,3) y=1/2x-1 1 solutions
Answer 279878 by Alan3354(30965) on 2011-01-13 20:12:05 (Show Source):
You can put this solution on YOUR website!A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
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Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 12
The slope, m = -3
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The slope of lines parallel is the same.
The slope of lines perpendicular is the negative inverse, m = +1/3
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Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
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For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com
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Linear-equations/394446: Write an equation of the line that passes through (1,-1) and is perpendicular to the line y = - 1/2x +6 1 solutions
Answer 279863 by Alan3354(30965) on 2011-01-13 19:46:08 (Show Source):
You can put this solution on YOUR website!A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
-----------------
Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 12
The slope, m = -3
------------------
The slope of lines parallel is the same.
The slope of lines perpendicular is the negative inverse, m = +1/3
----------------
Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
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For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com
|
Rectangles/394338: The length of a rectangle is twice its width. Find the dimensions of the rectangle in inches if its area
is 288 square inches. 1 solutions
Answer 279791 by Alan3354(30965) on 2011-01-13 17:11:59 (Show Source):
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Triangles/394287: if a triangle has a 90, 25, and 65 degree angles, and the length of the triangle is 2.3 cm, what are the length of the other too sides? 1 solutions
Answer 279774 by Alan3354(30965) on 2011-01-13 16:08:53 (Show Source):
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Travel_Word_Problems/394204: An airplane flies 490 miles with the wind and 340 against the wind in the same length of time. If the speed of the wind is 30, what is the speed of the airplane in still air? 1 solutions
Answer 279719 by Alan3354(30965) on 2011-01-13 12:46:20 (Show Source):
You can put this solution on YOUR website!The airspeed of the plane is the average (490 + 340)/2 = 415 mph
The windspeed is the difference = 75 mph, not 30.
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This problem has no solution.
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Inequalities/394203: Solve (v+1)^2-72=0 , where v is a real number.
Simplify your answer as much as possible.
If there is more than one solution, separate them with commas.
1 solutions
Answer 279715 by Alan3354(30965) on 2011-01-13 12:38:30 (Show Source):
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Exponents/394215: I think I am doing this problem wrong. If I am can you help me to find the mistake I am making?
simplify (10y^7)^4 (6y^-8)^-3 This is multiplication and what I have so far is
10^4(y^7)^4(1/6)^3(1/y^8)^3 then I got
10000y^11(1/216)(1/y^11)
I feel like that is not right please let me know what I am doing wrong. I have checked the book and I'm not understanding it a whole lot. 1 solutions
Answer 279697 by Alan3354(30965) on 2011-01-13 11:58:44 (Show Source):
You can put this solution on YOUR website!simplify

= 
= 
= 
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You added the exponents where you should have multiplied.

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This is multiplication and what I have so far is
10^4(y^7)^4(1/6)^3(1/y^8)^3 then I got
10000y^11(1/216)(1/y^11)
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Travel_Word_Problems/393818: Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy? 1 solutions
Answer 279549 by Alan3354(30965) on 2011-01-12 21:29:27 (Show Source):
You can put this solution on YOUR website!Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy?
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In 5 minutes, Tracy goes (36/60)*5 miles = 3 miles
Sarah's speed relative to Tracy is 14 mi/hr (50 - 36)
It takes 3/14 hour to catch Tracy, =~ 13 minutes.
8:05 + 13 = 8:18
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Travel_Word_Problems/393962: a freight train travels 1 mile in 1 minute 20 seconds. At this rate, how many miles will the train travel in 1 hour? 1 solutions
Answer 279511 by Alan3354(30965) on 2011-01-12 19:35:51 (Show Source):
You can put this solution on YOUR website!a freight train travels 1 mile in 1 minute 20 seconds. At this rate, how many miles will the train travel in 1 hour?
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1:20 = 80 seconds
1 hour = 3600 seconds
3600/80 = 45
--> 45 miles
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Evaluation_Word_Problems/393707: Suppose you are given the sum and the difference of two real numbers. How can you figure out what the numbers are themselves? Explain your reasoning clearly step by step. 1 solutions
Answer 279396 by Alan3354(30965) on 2011-01-12 11:38:13 (Show Source):
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Points-lines-and-rays/393714: The equations of two lines are 2x – y + 3 = 0 and 4x – 2y – 8 = 0. Find the horizontal distance and vertical distance between the two lines.
1 solutions
Answer 279392 by Alan3354(30965) on 2011-01-12 11:32:17 (Show Source):
You can put this solution on YOUR website!The equations of two lines are 2x – y + 3 = 0 and 4x – 2y – 8 = 0. Find the horizontal distance and vertical distance between the two lines.
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2x – y = -3
2x – y = 4 (2nd eqn divided by 2)
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y-int of 1st eqn = 3
y-int of 2nd = -4
Vertical distance = 7
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x-int of 1st = -1.5
x-int of 2nd = 2
Horiz distance = 3.5
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Points-lines-and-rays/393711: Determine the equation of each circle.
a) centre (2,-5) and radius 7
b) centre (-1,3) and passing through (4,1)
1 solutions
Answer 279389 by Alan3354(30965) on 2011-01-12 11:23:30 (Show Source):
You can put this solution on YOUR website! Determine the equation of each circle.
a) centre (2,-5) and radius 7

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b) centre (-1,3) and passing through (4,1)
Find the distance between the 2 points, that's the radius.
Then
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