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31230..31259 , 31260..31289 , 31290..31319 , 31320..31349 , 31350..31379 , 31380..31409 , 31410..31439 , 31440..31469 , 31470..31499 , 31500..31529, >>NextPolygons/414390: Find the area of polygon ABCD if the coordinates of the vertices are A(5,-1), B(9,2), C(9,9), and D(0,5). 1 solutions
Answer 290657 by Alan3354(31538) on 2011-02-26 15:22:17 (Show Source):
You can put this solution on YOUR website! Find the area of polygon ABCD if the coordinates of the vertices are A(5,-1), B(9,2), C(9,9), and D(0,5).
-------------------
A - B - C- D-A
+5 +9 +9 +0 +5
-1 +2 +9 +5 -1
-------------------
Add diagonals from upper left
5*2 + 9*9 + 9*5 = 10 + 81 + 45 = 136
Add diagonals from lower left
-1*9 + 2*9 + 9*0 + 5*5 = -9 + 18 + 25 = 34
-----------
Difference = 102
Area = 102/2 = 51 sq units
---------------------
PS It works for any # of points.
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Graphs/414338: decribe the y values as the line moves from left to right across the coordinate plane:7x+3y=24
1 solutions
Answer 290622 by Alan3354(31538) on 2011-02-26 10:54:44 (Show Source):
You can put this solution on YOUR website!decribe the y values as the line moves from left to right across the coordinate plane:7x+3y=24
----------
Solve for y
y = (-7/3)x + 8
------------
As x increases, y decreases. The slope is -7/3 so for each change of 1 in x, y decreases 7/3
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Travel_Word_Problems/414335: Thanks for your help.
Shouldn't the 500 meters be converted to .5km and the 1000 meters be converted to 1km.
Same as converting 26400ft. to miles, to get mph. 26400ft./5280ft. = 5 miles.
My calculation would be (.5km + 1km / 180km/h) x 60 mins. = .5 minutes.
Which equals 30 seconds.
Question 1157: Two trains, one 500 meters long and the other 1000 meters long, are traveling in opposite directions on parallel tracks. The first train is traveling at 100km/h and the other at 80km/h. How long will it take for the trains to pass each other from the moment the locomotives are at the same point?
Answer by khwang(438) (Show Source):
You can put this solution on YOUR website!
The diagram as below.
500 m 100 km/h ->
A<------>B (1st train)
C<------------->D (2nd train)
<- 80 km/h 1000 m
When they pass each other after t hrs,diagram as
A B
<------>
<------------->
C D
After t hrs, B moves 100 t km and C moves 80 t km.
So we have 100 t + 80 t = BC = CD + AB = 1000+ 500
So, 180 t = 1500, t = 25/3 hrs
[Or get t by (1000+ 500)/(100+80) directly.
Answer: it takes 25/3 hrs for the trains to pass each other
from the moment the locomotives are at the same point.
Or get t by (1000 + 500)/ (1000+ 60) directly.
1 solutions
Answer 290619 by Alan3354(31538) on 2011-02-26 10:45:06 (Show Source):
You can put this solution on YOUR website!The total length is 1.5 km
The relative speed is 180 km/hr = 3 km/minute
1.5/3 = 0.5 minutes
--------------------
You're right, the units have to match.
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Circles/414336: 24. A circle has radius 6 cm. Find the area in terms of of a sector of the circle with a 140° central angle 1 solutions
Answer 290617 by Alan3354(31538) on 2011-02-26 10:33:29 (Show Source):
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Graphs/414300: I am having the toughest time figuring out this problem. x/3+y/5=-1, x-3y=-3. how do i solve this equation.
1 solutions
Answer 290570 by Alan3354(31538) on 2011-02-26 07:54:33 (Show Source):
You can put this solution on YOUR website! x/3+y/5=-1, x-3y=-3. how do i solve this equation.
It's 2 equations.
--------------
x/3+y/5=-1 eqn 1
x - 3y= -3 eqn 2
------------------
5x +3y = -15 eqn 1 x15
x - 3y = -3 eqn 2
-------------------- Add
6x = -18
x = -3
---------
etc
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Mixture_Word_Problems/414153: how much water must be added to 300 gallons of 85% alcohol in order to reduce it to 70% alcohol? 1 solutions
Answer 290481 by Alan3354(31538) on 2011-02-25 18:51:25 (Show Source):
You can put this solution on YOUR website!300 gallons of 85% alcohol has 300*0.85 = 255 gallons of alcohol
-----------
For 255 gallons to be 70%, water has to be 30%
Total = 255/0.7 = 2550/7 =~ 364.286
Add 364.219 - 300 = 64.286 gallons of water
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Complex_Numbers/414147: How do you solve for x and y in this equation?
(1/2x+2)+(3y-2)i=4-7i
1 solutions
Answer 290479 by Alan3354(31538) on 2011-02-25 18:43:18 (Show Source):
You can put this solution on YOUR website!How do you solve for x and y in this equation?
(1/2x+2)+(3y-2)i=4-7i
------------------------
Why so much white space?
Is 1/2x (1/2)x? or 1/(2x)?
Use parentheses to eliminate ambiguities.
----------------
Anyway,
(1/2x+2) = 4
and
(3y-2) = -7
-------------
You can figure it out from that. The real coefficients are equal, and the coefficients of the imaginary parts are equal.
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Exponents/414146: please divide and simplify and type answer as a exponential notation with positive exponents for the following
(3b)^7
_______
(3b)^15
I have the answer 1/6561b^8 but I'm not sure this is correct. 1 solutions
Answer 290477 by Alan3354(31538) on 2011-02-25 18:35:44 (Show Source):
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test/414098: An objects altitude, in meters is given by the polynomial h+vt-9.8t, where is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 183 meters tall. If the initial speed is 39 meters per second, how high above the ground will the pebble be after 3 seconds? 1 solutions
Answer 290442 by Alan3354(31538) on 2011-02-25 15:23:14 (Show Source):
You can put this solution on YOUR website!An objects altitude, in meters is given by the polynomial h+vt-9.8t, where is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 183 meters tall. If the initial speed is 39 meters per second, how high above the ground will the pebble be after 3 seconds?
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I don't know where you got that equation, but:
h(t) = h+vt-9.8t
h(3) = 183 + 39*3 - 9.8*3
= 270.6 meters
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I would use h(t) = h + vt - 4.9t^2
h(3) = 183 + 39*3 - 4.9*9
= 255.9 meters
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Volume/414011: The circumference of the sphere is 26 meters. Find the volume.
I don't know how to find the volume with only the circumference given? 1 solutions
Answer 290401 by Alan3354(31538) on 2011-02-25 11:51:59 (Show Source):
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Surface-area/413968: if the lenght is 2 more than 4 times the width. the perimeter is 158.
is there something missing, i took it as saying the length is 4 times the width plus 2. is there a formula to break down perimeter backwards?
i came up with 15.4 as width, and 63.6 as lenght,to give me 158 for perimeter, but mainly thru trial and error method, i took a number times 4 then added 2 till i got 158, i know that wasnt the way it supposed to be done, was wondering what the formula and how work should be shown. 1 solutions
Answer 290396 by Alan3354(31538) on 2011-02-25 11:39:05 (Show Source):
You can put this solution on YOUR website!if the lenght is 2 more than 4 times the width. the perimeter is 158.
is there something missing, i took it as saying the length is 4 times the width plus 2. is there a formula to break down perimeter backwards?
i came up with 15.4 as width, and 63.6 as lenght,to give me 158 for perimeter, but mainly thru trial and error method, i took a number times 4 then added 2 till i got 158, i know that wasnt the way it supposed to be done, was wondering what the formula and how work should be shown.
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L = 4W + 2
Perimeter = 2L + 2W = 158
2(4W+2) + 2W = 158
4W+2 + W = 79
5W = 77
W = 15.4
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L = 63.6
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P = 2L + 2W is the only "formula" involved
PS It's length, not lenght
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Linear-systems/413738: Subsitution
{2x-3y=-9
3x=yt4
{8x-3y=4
7x=y+3
{6x-3y=5
x+2y=0
{10x-5y=-21
x+3y=0
{3x-y=1
2x-3y=10
{2x-y=-7
4x-3y=-11
**Steps to solving these problems**
1 solutions
Answer 290300 by Alan3354(31538) on 2011-02-24 20:09:09 (Show Source):
You can put this solution on YOUR website!You make an effort, show your work, we'll help you with it.
Tutoring is NOT doing problems for you, it's teaching you how to do them.
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Linear-equations/413589: Decide whether the pair of lines is parallel, perpendicular or neither.
4x+3y=3
3x+4y=9
Here is what I have:
4x+3y=3
3y=-4x+3
y=-4/3x + 3/3 (= 1)
3x+4y=9
4y=-3x+9
y=-3/4x + 9/4
What would that make this and can you help explain the difference? I am pretty sure that parallel has the same slope and perpendicular is -1/x. I maybe be totally wrong, but I think it is neither.
Help would be appreciated.
Thank you much,
Jeffrey G 1 solutions
Answer 290205 by Alan3354(31538) on 2011-02-24 14:46:36 (Show Source):
You can put this solution on YOUR website!Decide whether the pair of lines is parallel, perpendicular or neither.
4x+3y=3
3x+4y=9
Here is what I have:
4x+3y=3
3y=-4x+3
y=-4/3x + 3/3 (= 1)
3x+4y=9
4y=-3x+9
y=-3/4x + 9/4
What would that make this and can you help explain the difference? I am pretty sure that parallel has the same slope and perpendicular is -1/x. I maybe be totally wrong, but I think it is neither.
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The slope of the 1st eqn, m1 = -4/3
For the 2nd, m2 = -3/4
As you got above.
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If they're parallel, the slopes are equal. They're not parallel.
If they're perpendicular, the slopes are negative reciprocals. They're not perpendicular.
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The 2 slopes are inverses, but with the same sign --> neither.
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Linear-equations/413564: Hi, can anyone help figure out these two coordinate geometry problems?:
1) How do I find the equation of the line passing through (12,4) and perpendicular to y=3x+6? Leave answer in general form.
2) How do I find the equation of the line passing through (6,10) and perpendicular to 3x-4y=12? Leave answer in general form.
Thank you so much for your time! I have test on these tomorrow. 1 solutions
Answer 290199 by Alan3354(31538) on 2011-02-24 14:00:40 (Show Source):
You can put this solution on YOUR website!A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
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Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 12
The slope, m = -3
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The slope of lines parallel is the same.
The slope of lines perpendicular is the negative inverse, m = +1/3
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Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
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For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com
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Equations/413555: Good day. I have 9 equations that I need help solving. Thank you in advance.
1. x/2=-16 x/2 is a fraction.
2. Fractions: 3/8x-1/3x+6=1/6x
3. fractions: -1/4(x-8)+1/2(x-2)=x+9
4. Solve for k: F=kn
5. Solve for a: P=a+b+c
6. Solve the inequality, write in interval notation. 3x+5+x<2+2x+3
7. same as 6: -x+1+6x _> -2+2x+24
8. 11x+2>2(4x+1)-x+7
9. The length of a rectangular boat storage shed must be 4 meters more than the width, and the perimeter must be at least 108 meters. What is the range of values for the width? 1 solutions
Answer 290186 by Alan3354(31538) on 2011-02-24 13:17:28 (Show Source):
You can put this solution on YOUR website!1. x/2=-16 x/2 is a fraction.
No kidding.
Multiply both sides by 2.
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What sort of help do you need? What have you tried?
Repost, showing your efforts.
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2. Fractions: 3/8x-1/3x+6=1/6x
3. fractions: -1/4(x-8)+1/2(x-2)=x+9
4. Solve for k: F=kn
5. Solve for a: P=a+b+c
6. Solve the inequality, write in interval notation. 3x+5+x<2+2x+3
7. same as 6: -x+1+6x _> -2+2x+24
8. 11x+2>2(4x+1)-x+7
9. The length of a rectangular boat storage shed must be 4 meters more than the width, and the perimeter must be at least 108 meters. What is the range of values for the width?
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