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Equations/403295: I am stuck on a problem. I need to find the value of 'x' and simplify. I've tried 3 different ways to do it and none are coming out right, (according the the back of the book).
The equation is:
2(5x-3)-(2x-4)=5-(6x+1)
please help!!!
1 solutions

Answer 285196 by Alan3354(30993) About Me  on 2011-02-02 10:42:59 (Show Source):
You can put this solution on YOUR website!
2(5x-3)-(2x-4)=5-(6x+1)
10x-6 -2x+4 = 5 -6x-1
8x - 2 = 4 - 6x
14x = 6
x = 3/7


Rectangles/403243: how long is the side of the square if its area is 3 times the area of a square whose side is 5 cm?
1 solutions

Answer 285192 by Alan3354(30993) About Me  on 2011-02-02 10:26:38 (Show Source):
You can put this solution on YOUR website!
Area = 3*25 = 75
s+=+sqrt%2875%29+=+5sqrt%283%29
s =~ 8.66 cm


Triangles/403259: Which of the following os closest to the area of the shaded region? the figure is not drawn to scale. Use 3.14. The sides of the right triangle are given. (6cm, 10cm ,8cm) The radius of the circle is 2cm
1 solutions

Answer 285189 by Alan3354(30993) About Me  on 2011-02-02 10:17:56 (Show Source):
You can put this solution on YOUR website!
No shaded region is shown.


Travel_Word_Problems/403251: A car can be stopped from initial velocity 84 km/h to rest in 55 meters. Assuming constant acceleration, find the stopping time.
is it 4.72 seconds?
1 solutions

Answer 285188 by Alan3354(30993) About Me  on 2011-02-02 10:08:57 (Show Source):
You can put this solution on YOUR website!
A car can be stopped from initial velocity 84 km/h to rest in 55 meters. Assuming constant acceleration, find the stopping time.
is it 4.72 seconds?
---------------
Its average speed during the acceleration = 42 km/hr
42 km/hr = 42000/3600 m/sed = 35/3 m/sec
--------------
55 m/(35/3) m/sec =~ 4.714 seconds


Equations/403284: The sum of two numbers is 36 and their difference is 6. Find the larger of the two numbers.
Please help
1 solutions

Answer 285186 by Alan3354(30993) About Me  on 2011-02-02 10:03:14 (Show Source):
You can put this solution on YOUR website!
36/2 = 18
6/2 = 3
-------
18 ± 3 = 15 & 21


Polygons/403280: What is the perimeter of a regular pentagon with 8 cm sides?
1 solutions

Answer 285184 by Alan3354(30993) About Me  on 2011-02-02 10:00:22 (Show Source):


Coordinate-system/403267: Show that the points R (-1 , 2), K (5 , 2) and O (2 , 5) are the vertices of an isosceles triangle. Find the area of triangle RKO.
:) =)
1 solutions

Answer 285170 by Alan3354(30993) About Me  on 2011-02-02 08:58:07 (Show Source):
You can put this solution on YOUR website!
Show that the points R (-1,2), K (5,2) and O (2,5) are the vertices of an isosceles triangle.
-------------------
Find the lengths of RO and KO
s%5E2+=+diffy%5E2+%2B+diffx%5E2
For RO:
s%5E2+=+3%5E2+%2B+3%5E2+=+18
For KO:
s%5E2+=+3%5E2+%2B+3%5E2+=+18
They're the same length --> isoceles.
The length of KR = 6 --> not equilateral.
---------------------
---------------------
Find the area of triangle RKO.
----------------
Write the points in columns, repeating the 1st point
R K O R
-1 5 2 -1
+2 2 5 +2
----------
Add the diagonal products from upper left:
(-1*2) + 5*5 + 2*2 = 27
Add the diagonal products from lower left:
2*5 + 2*2 + 5*(-1) = 9
------------------
The area = 1/2 the difference
Area = (1/2)*(27-9) = 9 sq units


Graphs/403156: x2 + y2 = 8
x - y = 0
find the solutions to the system

1 solutions

Answer 285106 by Alan3354(30993) About Me  on 2011-02-01 21:58:14 (Show Source):


Polygons/403149: how do you find the number of sides of a polygon if the interior angles measure 140 degrees
1 solutions

Answer 285098 by Alan3354(30993) About Me  on 2011-02-01 21:45:11 (Show Source):
You can put this solution on YOUR website!
The exterior angles are 40º (180 - 140)
The sum of ext angles of ALL polygons = 360º
360/40 = 9 sides


Equations/403041: Solve.
(7+u)(3u-1)=0
(If there is more than one solution, separate them with commas.)
1 solutions

Answer 285042 by Alan3354(30993) About Me  on 2011-02-01 19:34:01 (Show Source):
You can put this solution on YOUR website!
(7+u)(3u-1)=0
-----------
For the product to be zero, one of the factors has to be zero.
7+u = 0
u = -7
------
3u-1 = 0
u = 1/3


percentage/402990: If my teacher was 225 pounds now he is 289 pounds. How much has he increased in weight?
1 solutions

Answer 285015 by Alan3354(30993) About Me  on 2011-02-01 18:06:35 (Show Source):


Numbers_Word_Problems/402980: Two numbers have a difference of 6. Their product is 775. What are the two numbers?
1 solutions

Answer 285010 by Alan3354(30993) About Me  on 2011-02-01 17:53:03 (Show Source):


Volume/402943: how many gallons of water does it take to fill a 30 inch by 50 foot cylinder

1 solutions

Answer 285008 by Alan3354(30993) About Me  on 2011-02-01 17:52:34 (Show Source):
You can put this solution on YOUR website!
Is 30 the radius, diameter, or length?


Equations/402966: I am trying to write an algebraic expreession for the following:
5 less than 2/3 of a number is 3.
1 solutions

Answer 284998 by Alan3354(30993) About Me  on 2011-02-01 17:30:41 (Show Source):
You can put this solution on YOUR website!
n = a number
(2/3)n - 5 = 3


Travel_Word_Problems/402960: brent takes a trip in his car. he covers the first 30 miles in one-half hour and the last 50 miles in one hour. find his average speed in m/h?

1 solutions

Answer 284996 by Alan3354(30993) About Me  on 2011-02-01 17:27:01 (Show Source):
You can put this solution on YOUR website!
brent takes a trip in his car. he covers the first 30 miles in one-half hour and the last 50 miles in one hour. find his average speed in m/h?
-----------
He goes 80 miles in 1.5 hours
80 mi/1.5 hr = 53 1/3 mph


Travel_Word_Problems/402967: a car travels at 60 miles per hour. At this rate how many miles can the car travel in 45 minutes?
1 solutions

Answer 284995 by Alan3354(30993) About Me  on 2011-02-01 17:25:19 (Show Source):
You can put this solution on YOUR website!
60 mph = 1 mile per minute
--> 45 miles


Divisibility_and_Prime_Numbers/402812: what is the prime factorization of 75
1 solutions

Answer 284936 by Alan3354(30993) About Me  on 2011-02-01 13:31:51 (Show Source):


Quadratic_Equations/402830: Can you please tell me how this problem gets solved? I'd like to see the steps from the problem to the answer
100x(to 3rd degree)and it's all in a square root sign
the answer is 10x(square root x)
I'm not sure how to arrive at the answer, I understand that 10 is the square root of 100, but what happens with the x's?
Thank you so much!
L
1 solutions

Answer 284931 by Alan3354(30993) About Me  on 2011-02-01 13:26:31 (Show Source):


Linear-systems/402828: May you help me with this problem:
g-10h=43
18=-g+5h
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284930 by Alan3354(30993) About Me  on 2011-02-01 13:21:52 (Show Source):
You can put this solution on YOUR website!
Do it like this one.
------------
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43


Linear-systems/402827: May you help me with this problem:
2q=7-5p
4p-16=q
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284929 by Alan3354(30993) About Me  on 2011-02-01 13:21:21 (Show Source):
You can put this solution on YOUR website!
Do it like this one.
------------
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43


Surface-area/402806: a square has a permeter of 36 cm find the length of ech side
1 solutions

Answer 284928 by Alan3354(30993) About Me  on 2011-02-01 13:18:54 (Show Source):
You can put this solution on YOUR website!
Divide 36 by the number of sides.


Linear-systems/402799: May you please help me with this problem:
5e+4f=9
4e+5f=9
The instructions are to use linear combinations to solve the linear system. Then check your solution. Thank you for your time.

1 solutions

Answer 284927 by Alan3354(30993) About Me  on 2011-02-01 13:16:54 (Show Source):
You can put this solution on YOUR website!
Do it like this one.
------------
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43


Linear-systems/402815: May you help me with this problem:
2v=150-u
2u=150-v
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284926 by Alan3354(30993) About Me  on 2011-02-01 13:15:49 (Show Source):
You can put this solution on YOUR website!
Do it like this one.
------------
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43


Linear-systems/402816: May you help me with this problem:
5s+8t=70
60=5s-8t
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284924 by Alan3354(30993) About Me  on 2011-02-01 13:15:16 (Show Source):
You can put this solution on YOUR website!
Do it like this one.
------------
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43


Linear-systems/402820: May you help me with this problem:
5y-20=-4x
4y=-20x+16
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284923 by Alan3354(30993) About Me  on 2011-02-01 13:14:43 (Show Source):
You can put this solution on YOUR website!
Do it like this one.
------------
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43


Linear-systems/402823: May you help me with this problem:
3x+7y=6
2x+9y=4
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284922 by Alan3354(30993) About Me  on 2011-02-01 13:14:03 (Show Source):
You can put this solution on YOUR website!
Do it like this one.
------------
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43


Linear-systems/402825: May you help me with this problem:
2p-q=2
2p+3q=22
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284921 by Alan3354(30993) About Me  on 2011-02-01 13:13:31 (Show Source):
You can put this solution on YOUR website!
Do it like this one.
------------
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43


Linear-systems/402821: May you help me with this problem:
3j+5k=19
j-2k=-1
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284920 by Alan3354(30993) About Me  on 2011-02-01 13:12:16 (Show Source):
You can put this solution on YOUR website!
3j+5k=19
j-2k=-1
------------
Multiply the 2nd eqn by 3 to make the coefficients equal
3j+5k=19
3j-6k=-3
---------- Subtract
-k = 22
k = 22
-------
j - 2k = -1
j -44 = -1
j = 43



Linear-systems/402819: May you help me with this problem:
6x+2y=5
8x+2y=3
The instructions are to use linear combinations to solve the linear system.
Then check your solution. Thank you for time.
1 solutions

Answer 284919 by Alan3354(30993) About Me  on 2011-02-01 13:08:57 (Show Source):
You can put this solution on YOUR website!
6x+2y=5
8x+2y=3
---------- Subtract
-2x = 2
x = -1
-----------
6x+2y=5
6(-1) + 2y = 5
2y = 11
y = 5.5


Problems-with-consecutive-odd-even-integers/402753: The sum of the squares of two consecutive positive odd integers is one hundred thirty. Find the two integers
1 solutions

Answer 284918 by Alan3354(30993) About Me  on 2011-02-01 13:06:06 (Show Source):
You can put this solution on YOUR website!
The sum of the squares of two consecutive positive odd integers is one hundred thirty. Find the two integers
---------------------
130/2 = 65
sqrt(65) =~ 8, the center
--> 7 & 9


Polynomials-and-rational-expressions/402795: I am a little rusty with algebra and was provided a study guide for an upcoming algebra test for an entrance exam. I need it solved so that I might gain an understanding as to how I am supposed to solve similar problems.
"Which of the following expressions represents the product of 3 less than twice x and 2 more than the quantity 3 times x?
A. -6 x^2 + 25x +6
B. 6 x^2 + 5x +6
C. 6 x^2 - 5x + 6
D. 6 x^2 - 5x - 6
E. 6 x^2 - 13x - 6 "
Thank you in advance!
1 solutions

Answer 284916 by Alan3354(30993) About Me  on 2011-02-01 12:56:26 (Show Source):
You can put this solution on YOUR website!
"Which of the following expressions represents the product of 3 less than twice x and 2 more than the quantity 3 times x?
-----------------
= (2x - 3)*(3x + 2)
= 6x%5E2+-+5x+-+6
D
-------------
A. -6 x^2 + 25x +6
B. 6 x^2 + 5x +6
C. 6 x^2 - 5x + 6
D. 6 x^2 - 5x - 6
E. 6 x^2 - 13x - 6 "