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Radicals/438457: I need help solving this equation.
Im not exactly sure how to type it and this is my best interpretation of it.
(fourth root of ((5x^2)-6))=(x)
1 solutions

Answer 303211 by Alan3354(30993) About Me  on 2011-04-20 14:55:05 (Show Source):
You can put this solution on YOUR website!
root%284%2C%285x%5E2-6%29%29+=+x
Raise both sides to the 4th power
5x%5E2+-+6+=+x%5E4
x%5E4+-+5x%5E2+%2B+6+=+0
%28x%5E2+-+2%29%28x%5E2+-+3%29+=+0
Can you finish it?


Rectangles/438464: The perimeter of a retangle is 64m. What are three possible measurements for the length and width? What is the area of these rectangles?
1 solutions

Answer 303209 by Alan3354(30993) About Me  on 2011-04-20 14:45:26 (Show Source):
You can put this solution on YOUR website!
Why 3? There are an infinite # of possibilities.
eg, 1 by 31 --> Area = 31
2 by 30 --> Are = 20
3 by 29 --> Area = 87
pi by 28.8584 --> Area = 90.6614
16 by 16 --> Area = 256 (the maximum area)


Graphs/438468: Could someone pleas show me how to solve the system by elimination method?
5x+3y=-7
7x-2y=13
1 solutions

Answer 303206 by Alan3354(30993) About Me  on 2011-04-20 14:37:04 (Show Source):
You can put this solution on YOUR website!
Multiply the 1st eqn by 2, and the 2nd by 3, then add them.
That will eliminate the y terms.


Geometric_formulas/438465: A segment has endpoints at (2, -15) and (8, 4). What is the midpoint of the segment?

1 solutions

Answer 303205 by Alan3354(30993) About Me  on 2011-04-20 14:35:49 (Show Source):
You can put this solution on YOUR website!
Find the average of x and y separately.


Linear-equations/438459: Where do the two graphs f%28x%29=x%5E2%2B2 and g%28x%29=x-8 intersect?
1 solutions

Answer 303203 by Alan3354(30993) About Me  on 2011-04-20 14:23:57 (Show Source):
You can put this solution on YOUR website!
Where f(x) and g(x) are equal.
f%28x%29=x%5E2%2B2+=+g%28x%29=x-8
x%5E2+%2B+2+=+x+-+8
x%5E2+-+x+%2B+10+=+0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-1x%2B10+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-1%29%5E2-4%2A1%2A10=-39.

The discriminant -39 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -39 is + or - sqrt%28+39%29+=+6.2449979983984.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1%2Ax%2B10+%29

---------
The solutions are not real numbers, so the graphs do not intersect.


Trigonometry-basics/438443: Prove the given statement is an identity
sin^2x (1+ tan^2)x = tan^2 x

1 solutions

Answer 303199 by Alan3354(30993) About Me  on 2011-04-20 14:16:41 (Show Source):
You can put this solution on YOUR website!
I think you mean
sin^2x (1+ tan^2(x)) = tan^2 x
sin^2 + sin^4/cos^2 = sin^2/cos^2
sin^2cos^2 + sin^4 = sin^2
sin^2(cos^2 + sin^2) = sin^2
sin^2 = sin^2



logarithm/438437: What is log base 2 of x = 3-log base 2 of 2x
1 solutions

Answer 303193 by Alan3354(30993) About Me  on 2011-04-20 14:04:37 (Show Source):
You can put this solution on YOUR website!
It's an unclear equation in x.


Proportions/438426: what is the slope of a binomial 2x+3
1 solutions

Answer 303192 by Alan3354(30993) About Me  on 2011-04-20 14:01:22 (Show Source):
You can put this solution on YOUR website!
A binomial does not have a slope.
At least 2 variables are necessary for a slope to exist.


Quadratic_Equations/438431: Solve the indicated variable. A=P(2+r)^2. r=? That should be the power of 2. I'm not sure how to start. I know I have to get the r by itself but the P is throwing me off. If the P wasn't there I would have squared both sides. Any help would be greatly appreciated.
1 solutions

Answer 303188 by Alan3354(30993) About Me  on 2011-04-20 13:50:20 (Show Source):
You can put this solution on YOUR website!
Solve the indicated variable. A=P(2+r)^2. r=?
----------
A=P%282%2Br%29%5E2
A%2FP+=+%282%2Br%29%5E2
2%2Br+=+sqrt%28A%2FP%29
r+=+sqrt%28A%2FP%29+-+2


Functions/438432: x^3-6x^2+7x+2=0
1 solutions

Answer 303187 by Alan3354(30993) About Me  on 2011-04-20 13:44:17 (Show Source):
You can put this solution on YOUR website!
1st, check for zeroes of ± 1 and ± 2.


Quadratic_Equations/438428: How would you solve the problem:
The height of a ball is measured by the function h(t)=-16t^2+112t-64, where h(t) is measured in feet and t is time in seconds.
(a) Evaluate h(2) and explain what dependent and independent variables represent.
(b) What is the height of the ball at 3 seconds?
(c) When is the ball at a height of 128 ft.?
1 solutions

Answer 303185 by Alan3354(30993) About Me  on 2011-04-20 13:40:29 (Show Source):
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How would you solve the problem:
The height of a ball is measured by the function h(t)=-16t^2+112t-64, where h(t) is measured in feet and t is time in seconds.
(a) Evaluate h(2) and explain what dependent and independent variables represent.
sub 2 for y
h(2) = -16*4 + 224 - 64 = 144 feet
h(2) is the height at 2 seconds, 2 is the time in seconds.
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(b) What is the height of the ball at 3 seconds?
h(3) = -16*9 + 112*3 - 64 = 128 feet
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(c) When is the ball at a height of 128 ft.?
128 = -16t^2 + 112t - 64
t^2 - 7t - 12 = 0
t = 3 seconds (ascending)
t = 4 seconds (descending)


Graphs/438423: Please help me graph this linear equation
5x-y=-8
1 solutions

Answer 303184 by Alan3354(30993) About Me  on 2011-04-20 13:34:15 (Show Source):
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It's a straight line, so you need 2 points.
at x=0, y = 8 --> (0,8)
at y=0, x = -1.6 --> (-1.6,0)
Plot them, draw a line thru them


logarithm/438410: Solve the equation for x. Round your answer to two decimal places, and do not include "x =" in your answer.
2x = 5.6962
1 solutions

Answer 303180 by Alan3354(30993) About Me  on 2011-04-20 13:18:20 (Show Source):
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2x = 5.6962
x = 2.8481
--> 2.85


Travel_Word_Problems/438307: if you are 16 miles from ann arbor, how long will it take to get there if your average speed is 42 miles per hour
1 solutions

Answer 303163 by Alan3354(30993) About Me  on 2011-04-20 10:57:23 (Show Source):


Probability-and-statistics/438339: Please help me with this question...I can't just figure it out.
A local restaurant offers 6 appetizers, 12 entrees, and 4 desserts. How many different meal combinations consisting of one appetizer, one entree, and one dessert could you order?
1 solutions

Answer 303158 by Alan3354(30993) About Me  on 2011-04-20 10:47:19 (Show Source):
You can put this solution on YOUR website!
6 appetizers, 12 entrees, and 4 desserts. How many different meal combinations consisting of one appetizer, one entree, and one dessert could you order?
----------
It's 1 of 6 times 1 of 12 times 1 of 4
6*12*4 = 288


Square-cubic-other-roots/438283: (x+9)^2=18
1 solutions

Answer 303151 by Alan3354(30993) About Me  on 2011-04-20 09:45:50 (Show Source):


Trigonometry-basics/438295: The sides of a triangle are 2cm, 3cm, and 4cm. Determine the measurement of the angle opposite the longest side.
1 solutions

Answer 303149 by Alan3354(30993) About Me  on 2011-04-20 09:43:24 (Show Source):
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Use the Cosine Law.
4%5E2+=+2%5E2+%2B+3%5E2+-+2%2A2%2A3%2Acos%28A%29
Solve for cos(A)


Travel_Word_Problems/438266: What is the speed of a race horse that runs 1500 miles in 125 seconds?

1 solutions

Answer 303146 by Alan3354(30993) About Me  on 2011-04-20 09:29:51 (Show Source):
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12 miles per second, which is almost twice the Earth's escape velocity.
He probably left the planet, which explains why didn't hear about it.


Rectangles/438276: a rectangle with length of 15 and width of 8 = _____sq ft
1 solutions

Answer 303143 by Alan3354(30993) About Me  on 2011-04-20 09:17:14 (Show Source):
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Area = length*width = 15*8 sq ft


Equations/438288: Please help me solve equation : 6[2(3.5+8.6)]
1 solutions

Answer 303142 by Alan3354(30993) About Me  on 2011-04-20 09:15:06 (Show Source):
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Please help me solve equation : 6[2(3.5+8.6)]
----------
This is not an equation, there's no equal sign.
You can simplify, or evaluate the expression, but there's nothing to solve.
----------
6[2(3.5+8.6)]
Work from the inside out.
= 6[2(12.1)]
= 6*2*12.1
= 145.2


Trigonometry-basics/438285: If the cos B = 0.9659, find m ∠B to the nearest degree.
1 solutions

Answer 303141 by Alan3354(30993) About Me  on 2011-04-20 09:02:07 (Show Source):
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B = 15 degs
Do you not have a calculator?


Distributive-associative-commutative-properties/438282: How do I solve for the variable s in this problem
g=cst
1 solutions

Answer 303139 by Alan3354(30993) About Me  on 2011-04-20 08:51:20 (Show Source):
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Divide both sides by ct


Miscellaneous_Word_Problems/438270: A 65-inch pipe is cut into two pieces. One piece is four times the length of the other. Find the lenghts of the two pieces.
1 solutions

Answer 303138 by Alan3354(30993) About Me  on 2011-04-20 08:39:42 (Show Source):
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Hint: x + 4x = 65


Equations/438278: i love some one who i never met him he doesn't know me but the weird is that he accepted me on facebook and i saw hime one day in a restursnt but i'm sure he didn't realize me so im really in love with him the question is: how can i make him fall in love with me?

1 solutions

Answer 303136 by Alan3354(30993) About Me  on 2011-04-20 08:38:39 (Show Source):
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Is he good at math?


Length-and-distance/438239: Please help with this question,I'm really stock.I need this tomorrow.Thank you..
A cross country race course on flat ground has runners,Jedd and Rodney, heading from point A for 3.5km on a bearing of 047degrees temperature to point B. From B they turn and run for 2.8km on a bearing of 342degrees temperature to point C. They then run back to point A.
(a.) Determine the distance from C back to A.
(b.) At what bearing does the course follow from C back to A?
1 solutions

Answer 303135 by Alan3354(30993) About Me  on 2011-04-20 08:36:11 (Show Source):
You can put this solution on YOUR website!
A cross country race course on flat ground has runners,Jedd and Rodney, heading from point A for 3.5km on a bearing of 047degrees temperature to point B. From B they turn and run for 2.8km on a bearing of 342degrees temperature to point C. They then run back to point A.
(a.) Determine the distance from C back to A.
(b.) At what bearing does the course follow from C back to A?
-----------------
These degrees have nothing to do with temperature ??? They're compass headings. No wonder you're "stock."
------------
0 degrees is North. 047 degs is 47 degrees to the East of North. If you make a sketch, you'll see that angle CBA = 115 degrees (not a heading)
Now you have a triangle with 2 sides and the included angle.
Use the Cosine Law to find side AC, side b.
b%5E2+=+a%5E2+%2B+c%5E2+-+2%2Aa%2Ac%2Acos%28115%29
b%5E2+=+12.25+%2B+7.84+-+2%2A3.5%2A2.8%2Acos%28115%29
b%5E2+=+28.3733
b =~ 5.32666 km
= distance from C to A
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---------------
Find angle C using the Law of Sines:
b/sin(115) = 3.5/sin(C)
sin(C) = 3.5*sin(115)/b =~ 0.5955
Angle C = 36.55 degs (not a heading)
---------------------
The heading from A to C = 047 - 36.55 =~ 010
From C to A is the reciprocal,
Heading = 190 degrees


Pythagorean-theorem/438228: b=3, c=7
1 solutions

Answer 303119 by Alan3354(30993) About Me  on 2011-04-20 06:39:31 (Show Source):
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And? Do you have a question?


Trigonometry-basics/438253: If x+=+%28a%29+sin+%28theeta%29+-+%28b%29+cos+%28theeta%29 and y+=+%28a%29+cos+%28theeta%29+%2B+%28b%29+sin+%28theeta%29, show that %28x%29%5E2+%2B+%28y%29%5E2+=+%28a%29%5E2+%2B+%28b%29%5E2 .

1 solutions

Answer 303118 by Alan3354(30993) About Me  on 2011-04-20 06:36:22 (Show Source):
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It's theta, not theeta.
-----------
I got an email and looked it up, and it is "theeta" in some other language.
I don't know what that language is, tho.
-----------
I replied to you email questions, but I get a kick-back on the email I send.


Trigonometry-basics/438254: Sketch the graphs of y+=+%282+cos+x+%2B+sin+x%29+%2F+%28cos+x%29 for 0 degrees is smaller than or equal to x and 360 degrees is greater than or equal to x.

1 solutions

Answer 303117 by Alan3354(30993) About Me  on 2011-04-20 06:35:16 (Show Source):
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Sketch the graphs of y+=+%282+cos+x+%2B+sin+x%29+%2F+%28cos+x%29 for 0 degrees is smaller than or equal to x and 360 degrees is greater than or equal to x.
------------------
y+=+2+%2B+tan%28x%29
It's the tangent shifted up by 2.
------------
dl the FREE graph software at
http://www.padowan.dk


Travel_Word_Problems/438116: Matt says he's faster than Alex. He rode 20 feet in 5 minutes. What is Matt's speed, and is he faster than Alex?
1 solutions

Answer 303046 by Alan3354(30993) About Me  on 2011-04-19 21:06:01 (Show Source):
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20 ft/5 min = 4 ft/min
It's hard to imagine anyone slower than that unless he's riding a turtle.


Quadratic_Equations/438123: Use the quadratic formula to solve the equation.
0=x^2-2x-15
1 solutions

Answer 303045 by Alan3354(30993) About Me  on 2011-04-19 21:02:23 (Show Source):
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-2x%2B-15+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-2%29%5E2-4%2A1%2A-15=64.

Discriminant d=64 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--2%2B-sqrt%28+64+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-2%29%2Bsqrt%28+64+%29%29%2F2%5C1+=+5
x%5B2%5D+=+%28-%28-2%29-sqrt%28+64+%29%29%2F2%5C1+=+-3

Quadratic expression 1x%5E2%2B-2x%2B-15 can be factored:
1x%5E2%2B-2x%2B-15+=+%28x-5%29%2A%28x--3%29
Again, the answer is: 5, -3. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-2%2Ax%2B-15+%29



Expressions-with-variables/438125: I am lost, here is the question... y varies directly as the square of x. If y=162 when r=9, find y when r=3
1 solutions

Answer 303044 by Alan3354(30993) About Me  on 2011-04-19 21:01:09 (Show Source):
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If you mean it varies with r:
--------
y = k/r^2
You can find the constant
162 = k*(9^2) = k*81
k = 2
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at r=3, y = 2*3^2
y = 18
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You don't have to find the constant
at r = 3, y = 162/(9/3)^2 = 162/9 = 18
r is 1/3, so y is (1/3)^2 of 162
= 18