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Welcome to shree840's "About Me" page!shree840(260)   About shree840: I live in PLANO,TX I am certified high school math teacher. I do not have any contract for this year and I am tutoring only one to one. What did shree840 acccomplish on this site?
Comment from student: I'm so sorry I never said thank you for helping me with my problem. I "liked" you on Facebook, then I got distracted and forgot to come back. If you're willing, I need some more help on the same problem. It seems they wanted me to show my work even though they never asked for it. I've tried to do the problem myself but something tells me I'm a million miles away. Could you check it out for me? I'd appreciate it. -2x^2+76x+430 -2(x^2-38*x-215) = 2*(x^2-38*x-215) Expanded term 2 by using associative properties (x2-38*x-215) which becomes 2*x2-2*38*x-2*215 Multiply numerator integers Becomes 2*x2-76*x-2*215 2*x2-76*x-2*215 multiply numerator integers it becomes 2*x2-76*x-430 2*x(x-43) +5(x-43) Expanded term 2* by using associative property on (x-43) It becomes 2*x*x-2*43+5*(x-43) Look at 2*x*x-2*43+5*(x-43) Multiplied numerator integers it becomes 2*x*x-86*x+5*(x-43) Look at 2*x*x-86*x+5*(x-43) Reduce similar several occurrences of x to x2 it becomes 2*x2-86 *x+5*(x-43) Look at 2*x2-86*x+5*(x-43) Expanded term 5 by using associative property on (x-43) it becomes 2*x2-86*x+5*x-5*43 Look at 2*x2-86*x+5*x-5*43 Multiplied numerator integers it becomes 2*x2-86*x+5*x-215 Eliminate similar terms, -86*x5*x replacing them with (-86+ 5)* x It becomes 2*x 2+ (-86+5)*x-215 Look at 2*x2+ (-86+5)*x-215 Added fractions or integers together it becomes 2*x2+ (-81)*x-215 Look at 2*x2 + (-81)*x-215 Removed extra sign in front of -81 it becomes 2*x2-(-81)*x-215 Look at 2*22+ (-81)*x-215 Remove unneeded parentheses around factor 81 it becomes. 2*x2-81*x-215 Result: -2(x^2-43x+5x-215 = -2(x+5) (x-43) Comment from student: Thank you for your help, shree840! Comment from student: thank you so much you were a big help,relly you are just fantastic, may God bless you..xxxx Comment from student: shree840, thank you for spending your free time answering my question. Comment from student: thank you so much Comment from student: I'm not 100% sure that I understand your answer to my problem, but thanks for answering it so quickly Joe Comment from student: Thank you for your help! That is the answer that I originally got but I just wanted to make sure! Comment from student: Thank you so much! You've been very helpful! Comment from student: Thank you so much for your help! Comment from student: Thanks for your help. My professor is kind of funny ha! Well the question is There are 3 children. What is the probability that one is a boy given that one is a girl? Comment from student: There's only one person playing and there is only one deck. Thank you for your help! Comment from student: Thank you so much for your help! It's really obvious to me now! Comment from student: thank you so much for your help I appreciate it I will recommend this site to others God Bless Comment from student: Thanks for the help!! Comment from student: thank you! :) Comment from student: Thank you for your response. It helped me a lot! You guys are great!! Comment from student: Bless you and thank you so much Comment from student: Thank You So Much!!! Comment from student: Thank you Comment from student: Thank you! Comment from student: thanks Comment from student: How did you get the answer to : Question 432185: The sum of two numbers is 15 and the difference of their reciprocals is 1/10. Find the numbers. Comment from student: Comment from student: thanks for answering but that didnt help me much. Comment from student: Thank you so much I figured out what I did wrong....It was a basic math error! I was dividing 300 by 144 instead of 3000. I appreciate your qick response ! Comment from student: Thanks for helping to solve my math problem it was really tough. I really appreciate the help fantastic! job. thanks again. Comment from student: Thanks so much for all your help. I solved it differently and came up with the same answer. I never really considered this method. Thanks so much! =D Comment from student: I appreciate your help, but I'm not sure how you got s^4-2s^2y^2+t^4 when there is no "y". Comment from student: Thank you so much for your quick and helpful response. I will request your paid help in the future. Comment from student: Thank You :) I was sure about 12 anyway, and 5 and 8 I typed in wrong. Comment from student: Thank you very much for your help! You answered my question politely and quickly =] Comment from student: Thank you so much! When you started to explain it and work out the problem, I started to understand and remember what the teacher had said. This will help me a lot in furture problems. I appreciate you're help and patience. *Hugs* ~A.R.D Comment from student: (3xy^-2)^2 / (x^3) (-a^2b)^3 / (2b-1) (4x)^-3 / (y^3) (16)^3/4 11^1/2.11^3 These are fractions / and this seperates the numerator from the demoninator. I hope this helps...thanks! Comment from student: Wow, thank you so much man! See ya ! :) =) Comment from student: Thanks! your answer was correct :) Comment from student: Thank you for the help, I really appreciate it! Comment from student: Thank you for the help, I really appreciate it! Comment from student: Thank you but I don't get how you did it still...:-/ Comment from student: Thank you so much for the help in answering my question, I now understand what it means and how to locate my points. I will be sure to tell other classmates about the help that you provided. Thanks again. Amccauley@hotmail.com Comment from student: Comment from student: Thank you so much for your help this has gave me a better understanding so I will be able to do my other problems. Comment from student: Thank you so much for your help. I'm not a student, but I am trying to cut a shelf for a corner unit. It's clear I should have paid more attention in school 30 years ago! Thank you again, sir. Comment from student: thanks so much! Comment from student: thank you again! Comment from student: thank you! Comment from student: thank you so much! |
