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Welcome to mathstutor494's "About Me" page!mathstutor494(95)   About mathstutor494: Retired engineer. Volunteer math tutor for high and middle schools algebra, arithmetic, geometry and trigonometry. What did mathstutor494 acccomplish on this site?
Comment from student: Thank you so much for helping me with my homework Comment from student: thank you very much for helping me. i HIGHLY appreciate it. thank you very much(: Comment from student: thnaks, sir for helping it was a really good shortcut for solving that problem &wish you a very happy new year. Comment from student: Thank you so much for the help. It really is awesome that I could use your help.. Have a wonderful day!!! Thanks Again!!!! Comment from student: thanks a lot sir Comment from student: Thank you:) Comment from student: THANKS A LOT. Comment from student: (I thought it was erroneous, too. {It's 2log (subscript"b").} I think there is an error in signs). If the orig. EQ. is still unsolvable, I'm providing an alternate (below).I really appreciate your fast reply and your effort. Note: in below, the term "2-a" is NOT log b. (Solve for x): log b(x) = 2-a + log b (a^2*b^a)/b^2) Comment from student: Thank you! Comment from student: Thank you very much! Comment from student: thank y0u so much .. thanks .. very well thank y0u .. Comment from student: Thank you, mathstutor494! Your solution pretty much explains the logic behind the question. Comment from student: thanks very much for ur answer Comment from student: thank you very much ... :D Comment from student: Thank You so much, and I will recommend you to everybody I know that needs help :-)! Comment from student: thanks Comment from student: Comment from student: Thank you so much your help! It really means a lot. :) Comment from student: Thank you for the help. Comment from student: Thank you for the help. |
