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### Welcome to math-vortex's "About Me" page!

math-vortex(472)
About math-vortex: I tutor middle school and high school math in Seattle (USA). Students say that my explanations are "easy to understand." Email me at math.in.the.vortex@gmail.com with your math questions.

#### What did math-vortex acccomplish on this site?

• math-vortex has no published lessons yet.
• math-vortex has no published solvers yet.
• math-vortex wrote 472 solutions (see them).

Comment from student: Thank You Ms. Figgy! Your a life saver! Thanks Again!

Comment from student: Mrs. Friggy, Thank you so much. That is what I thought. It is from the Trichotomy law from Algebra that actually states that two numerical values must be related in exactly one of three possible relationships. I just had to make sure I was correct. Thank you for your help!

Comment from student: Mrs. Friggy, Thank you so much. That is what I thought. It is from the Trichotomy law from Algebra that actually states that two numerical values must be related in exactly one of three possible relationships. I just had to make sure I was correct. Thank you for your help!

Comment from student: Mrs. Friggy, Thank you so much. That is what I thought. It is from the Trichotomy law from Algebra that actually states that two numerical values must be related in exactly one of three possible relationships. I just had to make sure I was correct. Thank you for your help!

Comment from student: Thank you so much! That was exactly the answer I needed!

Comment from student: Thank you so much Mrs. Figgy. Statistics and Probability problems are not my favorites. I will certainly email you if I stumble on other problems. Again, Thanks!

Comment from student: Thank you so much!

Comment from student: I kinda figured it out and I think for now I'm going to try and work thru it but thanks so much for your response

Comment from student: Thank you!!!

Comment from student: Thanks so much!! :-)

Comment from student: ok. I understand all the way up to n=1/(sqrt(50)) how did you come up with (sqrt(50))/50 = 5(sqrt(2))/50 = (sqrt(2))/10. I guess what im a trying to say is how do you simplify the first expression of n =1/(sqrt(50))? thank you so much for your time.

Comment from student: Dear Mrs. FIggy: Wow. Thank you so much! I was trying to help my daughter with her homework; I am nooooo good at Algebra, and I am not 100% sure I followed, but I think it is reasonably clear to me, which is progress for me! I can't wait to share the solution with her! Thanks again! Jane (Mom) and Sarah (grade 9 algebra student)

Comment from student:

Comment from student: Thank you so much you were very helpful! Alex

Comment from student: Thanks I have a question. You have the area of a circle as A=2*pi*r^2 my book say A=pi*r^2. Could you double check that for me? I don't understand. Thank you

Comment from student: Dear Ms.Figgy, Thank you so much for helping me to solve this problem. You have taken me step by step so that I could see where I made mistakes, and also a process that was easy to understand. This was very helpful and I will be sure to pass on the word to my friends along with this helpful website.

Comment from student: Thanks for the help ***Ms. Vortex. I would +1 you but I dont have on those accounts :/

Comment from student: Thanks for the help Mr. Vortex. I would +1 you but I dont have on those accounts :/

Comment from student: Thank you very much. You're a big help. Till next time.

Comment from student: Thank you so much for working the steps out with the whole problem. It helped me a lot.

Comment from student: Thank you. I worked on it for hours trying to write the equation, but it just ended up being wrong. It is interesting to note that this particular sequence is named after a mathematics "star". Again, thank you for your help.

Comment from student: Thank you so much. Gina

Comment from student: You are right that's what I kept doing. Thank you so much I get it now.

Comment from student: Thank you so much! Plain English. I wish more teachers put it so succinctly and in simpler relatable terms. I spent hours trying to Google this to no avail.

Comment from student: Thanks so much for the help! i really appreciate it :) -MeLissa

Comment from student: Thank you Ms. Figgy...I haven't found anyone that breaks it down the way you do..Again thank you soooo much!!

Comment from student: She solved the problem in an extremely detailed way showing work and explanations. It helped me so much and I truly appreciate it.

Comment from student: Thank you for being so helpful.I will recommend you to all of my friends

Comment from student: thank you for your time that was a great explaination

Comment from student: Hello, thank you so much! This really helped me understand the process to how to answer the question. Again, thank you!

Comment from student: Thank you! Yes, this did help.

Comment from student: Thank you so much math-vortex....

Comment from student: Hello and thank you for your help. The problem reads: the value, v, in the hundreds of dollars, of Bob's stamp collection is 12 dollars more than 1/3 of the age, t(in years). Then graph the equation and use the graph to determine the value of Bob's collection if it is 9 years old. Thank you again, Janice

Comment from student: Thank you!!!!!!

Comment from student: I am so greatful for their help . They trully help me out when i needed them

Comment from student: thanks a bunch for helping me on that problem! it makes alot more sense now. :D :D

Comment from student: Sorry about the information, i was kinda in a hurry. i have to use the Pythagorean Theorem on the triangle, and the numbers to the angles are a = 5, b = 12, c = ?. So c is the missing side. I think i'm supposed to plug in the numbers to the sides of the triangle, but I'm not sure what to do after that. Do you think you may help me figure out how to do this one correctly so i'll know how to figure out the others? Thank you :)

Comment from student: Thank you so very much, as my husband is going back to college at the age of 55, to take a Business Management and he is trying to refresh his Algebra, and everyone one in a while he comes up with a problem that trips him up, and this was one of them. So thank you very much. D.Abell

Comment from student: They are the midpoints of adjacent sides- and thank you for your time