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### Welcome to jrfrunner's "About Me" page!

jrfrunner(365)
About jrfrunner: professional with masters degree in statistics

#### What did jrfrunner acccomplish on this site?

• jrfrunner has no published lessons yet.
• jrfrunner has no published solvers yet.
• jrfrunner wrote 364 solutions (see them).

Comment from student: Thank you =)

Comment from student: where was the problem solved already? I didnt see it I did see some with different numbers in the equation...

Comment from student: Thank u sooo much that really helped! now i have an idea on how to answer a couple others just like that one! thxs again!(:

Comment from student: thank you very much

Comment from student: tnx you...

Comment from student: tahnk you :)

Comment from student: thank you soo much god bless :)

Comment from student: thank you

Comment from student: you have me lost but thank you for trying

Comment from student: Thank you so very much:))

Comment from student: Thank you so much!

Comment from student: Thank you very much!

Comment from student: thank you so much like i said i was lost on thhs one

Comment from student: Thank You so much. I am 68 and taking algerba to enchance some of my brain cells. I took intermediate Algerba 7 years ago and I could not remember the graph. It is so nice to find a web site that I can turn to when I need help. Thanks for being there Thanks again, dollyruth.

Comment from student:

Comment from student: Thank you very much for everything. It was really wonderful to know how to solve this types of problems.

Comment from student:

Comment from student: Oops, sorry I typed an answer in the wrong box. Thanks for your answer.

Comment from student: &#8730;7=2.65, 2.65-3=-0.35, -0.35^3=-0.04

Comment from student: thanks for the help!

Comment from student: Thank you

Comment from student: jrfrunner; Thank you for your help. That is the answer, but what is in the middle of a Venn diagram? P(M and W) = ?? also P(M or W). I have done these problem a number of times but this one throws me in regards to the 40% of all students major in business. Sincerely stewbaby

Comment from student: Thank you so much for your help. Really appreciate it.

Comment from student: The sum of two angles is 130. Four times the complement of the first angle added to the three times the supplement of the second angleis equal to 460. Find both angles

Comment from student: Thank you so much for the help i was getting alittle confused with it, Thank you again so much was a great help

Comment from student: Thank you... I already had the answers, but now I know they're right!! Next time if I have a problem I'll try to post it earlier. I really appreciate it.

Comment from student: Thank you sir for answering this question for me, much appreciated!

Comment from student: Thanks soo much for taking the time to help me! I reall, really appreciate it :)

Comment from student: thanks a lot jrfrunner.u helped me without any payment,that's truly a deserving thing.but sorry ,i can't pay u for it except my thanks. and i must say ,u r doing a great job!

Comment from student: Thanks so much for your time! Very quick response, and detailed (I made the two mistakes you mentioned and found them, assumed there were more hiding in there haha)

Comment from student: The rectangle is dived into four small triangles within the quadrilateral....does that help any?

Comment from student: Thank you!

Comment from student: thank you so much. :)

Comment from student: Thank you for your help. I really appreciate your effort.

Comment from student: Thank you for your response. I was assuming that the probability would be 0 since you can never really get the last red chip since you are replacing the chip each time it is drawn. I am grateful to you.

Comment from student: Thank You so much

Comment from student: Thanks,helped a lot

Comment from student: Thank you very much for your help.

Comment from student: Thank you for the help. It is much appreciated.

Comment from student: Thank you for clearing up the last digit for me!

Comment from student: thank you so much!!!

Comment from student: how do you do the first one.

Comment from student: I want to thank you TREMENDOUSLY for your help. You explained it thoroughly enough that I have confidence that I can do this! Thank you so much!!!

Comment from student: the ratios are much simpler, thanks. but then i worked it from the ratios to find what x is and i got .71 which is still wrong. so i don't know what i'm doing wrong. thanks for your help though!