SOLUTION: There were three candidates for the position of the chairman of a college Mr. X, Mr. Y and Mr. Z whose chances of getting appointments are in the ratio 4:2:3 respectively. The pr

Question 970604: There were three candidates for the position of the chairman of a college Mr. X, Mr. Y and Mr. Z whose chances of getting appointments are in
the ratio 4:2:3 respectively. The probability that Mr. X if selected would introduce computer education in the college is 0.3. The probabilities of Mr. Y and Mr. Z doing the same are 0.5 and 0.8 respectively. What is the
probability that there was computer education in the college?

Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
There were three candidates for the position of the chairman of a college Mr. X, Mr. Y and Mr. Z whose chances of getting appointments are in
the ratio 4:2:3 respectively. The probability that Mr. X if selected would introduce computer education in the college is 0.3. The probabilities of Mr. Y and Mr. Z doing the same are 0.5 and 0.8 respectively. What is the
probability that there was computer education in the college?
Solution:
First we compute the probability that there was NO computer education in the college.
P(C') = =
Therefore, the probability that there was computer education in the college is
P(C) = 1 - P(C') = 1 - 22/45 =
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