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123 ("year-11") students chose the courses they wanted at the school prom dinner.
75 chose a starter, 106 chose a main course and 81 chose a dessert.
67 chose a main course and dessert,
64 chose a starter and a main course
while 49 chose a starter and dessert.
Everybody ordered at least one course.
Find the probability that a student chosen at random chose all three courses
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The number of all students who chose all three cources is
123 - (75 + 106 + 81 - 67 - 64 -49) = 41
according to the Inclusion-Exclusion principle.
Therefore, the probability that a student chosen at random chose all three courses is
= . ANSWER
Solved.
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On inclusion-exclusion principle, see this Wikipedia article
https://en.wikipedia.org/wiki/Inclusion%E2%80%93exclusion_principle
To see many other similar (and different) solved problems, see the lessons
- Counting elements in sub-sets of a given finite set
- Advanced problems on counting elements in sub-sets of a given finite set
- Challenging problems on counting elements in subsets of a given finite set
- Selected problems on counting elements in subsets of a given finite set
- Inclusion-Exclusion principle problems
in this site.
Happy learning (!)