SOLUTION: Average Score = 88
Standard Deviation = 5
*Assuming that the scores were normally distributed:
Number of students who took test = 1250
--what percentage of students would have
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Question 1168630: Average Score = 88
Standard Deviation = 5
*Assuming that the scores were normally distributed:
Number of students who took test = 1250
--what percentage of students would have a score less than 80?
a. What is the z-score?
b. What is percentage?
MY ANSWER:
a.-1.60
b. 05.48 %
-hi can you check my answer if it is correct?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
You are correct.
z=(x-mean)/sd
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