SOLUTION: If the average systolic blood pressure is 120 and the standard deviation is 10, find
the probability that a randomly selected person will have a blood pressure less than
108. A
Algebra.Com
Question 1160943: If the average systolic blood pressure is 120 and the standard deviation is 10, find
the probability that a randomly selected person will have a blood pressure less than
108. Assume the variable is normally distributed.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
average is 120.
standard deviation is 10.
probability that a randomly selected person will have a blood pressure less than 108 can be calculated as follows:
z = (x-m) / s
z is the z-score
x is the raw score
m is the raw mean
s is the standard deviation
formula becomes:
z = (108 - 120) / 10 = -12 / 10 = -1.2
look up in z-score table for area to the left of z-score of -1.2.
table says area to the left of that z-score is equal to .11507
that area means that the probability of getting a z-score less than -1.2 is .11507.
that also means that the probability of getting a raw score less than 108, when the mean is 120 and the standard deviation is 10, is also .11507.
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