SOLUTION: There are 5 quarters, 2 dimes and 6 pennies in a jar. If you pull three at random what is the probability that you will have three coins with the sum of 36 cents?

Question 1094336: There are 5 quarters, 2 dimes and 6 pennies in a jar. If you pull three at random what is the probability that you will have three coins with the sum of 36 cents?
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

You choosing 3 of the 13 coins in the jar; the number of ways to do that is "13 choose 3":

In order to get a total value of 36 cents, the three coins must be 1 quarter, 1 dime, and 1 penny.

So you need to choose 1 of the 5 quarters ("5 choose 1" = 5 different ways), 1 of the 2 dimes ("2 choose 1" = 2 ways), and 1 of the 6 pennies ("6 choose 1" = 6 ways).

So the total number of ways to get 1 of each coin is

Then the probability of getting that desired outcome is the total number of way to get the desired outcome, divided by the total number of ways of picking 3 of the 13 coins:

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