SOLUTION: Need help with this Calculus problem please. Find an equation for the line tangent to the curve when x has the first value. y=3√x x=4 x=9

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Question 1019792: Need help with this Calculus problem please.

Find an equation for the line tangent to the curve when x has the first value.
y=3√x
x=4
x=9
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
If y+=+3sqrt%28x%29, then the derivative is the function dy%2Fdx=3%2F%282sqrt%28x%29%29
==> when x = 4, dy%2Fdx+=+3%2F4, which is the slope of the line tangent at the point (4,6) of the curve.
==> y+-+6+=+%283%2F4%29%28x-4%29
<==> 4y - 24 = 3x - 12
<==> 3x - 4y +12 = 0 is the tangent line.
For x = 9, the procedure is the same.