SOLUTION: Arnold Palmer and Tiger Woods are two of the best golfers to ever play the game. To show how these two golfers would compare if both were playing at the top of their game, the foll

Question 1197931: Arnold Palmer and Tiger Woods are two of the best golfers to ever play the game. To show how these two golfers would compare if both were playing at the top of their game, the following sample data provide the results of 18-hole scores during a PGA tournament competition. Palmer’s scores are from his 1960 season, while Woods’s scores are from his 1999 season (Golf Magazine, February 2000).
Palmer, 1960 Woods, 1999
n_1 = 112 n_2 = 84
x_1 = 69.95 x_2 = 69.56
Use the sample results to test the hypothesis of no difference between the population mean 18-hole scores for the two golfers.
a. Assume a population standard deviation of 2.5 for both golfers. What is the value of the test statistic?
b. What is the p-value?
c. At α = .01, what is your conclusion?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Ho: m1 - m2 = 0
Ha: m1 - m2 > 0
α = .01
t=(x̄1 - x̄2)/sqrt ((s1^2/n1)+(s2^2/n2))
t=(69.95-69.56)/sqrt ((2.5/112)+(2.5/84)) = 1.71
p(z > 1.71) = .0436 > .01 , Fail to reject Ho.
Sample results indicate there is no difference between the population mean 18-hole scores for the two golfers.

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