SOLUTION: "Dalmatian Darnation," by Kathy Sparling A greedy dog breeder named Spreckles Bred puppies with numerous freckles The Dalmatians he sought Possessed spot upon spot The more spots

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Question 1098603: "Dalmatian Darnation," by Kathy Sparling
A greedy dog breeder named Spreckles Bred puppies with numerous freckles
The Dalmatians he sought Possessed spot upon spot The more spots, he thought, the more shekels. His competitors did not agree That freckles would increase the fee. They said, “Spots are quite nice But they don't affect price; One should breed for improved pedigree.” The breeders decided to prove This strategy was a wrong move. Breeding only for spots
Would wreak havoc, they thought. His theory they want to disprove.
They proposed a contest to Spreckles Comparing dog prices to freckles.
In records they looked up One hundred one pups: Dalmatians that fetched the most shekels. They asked Mr. Spreckles to name An average spot count he'd claim To bring in big bucks. Said Spreckles, “Well, shucks, It's for one hundred one that I aim.” Said an amateur statistician Who wanted to help with this mission. “Twenty-one for the sample Standard deviation's ample:
They examined one hundred and one Dalmatians that fetched a good sum.
They counted each spot, Mark, freckle and dot And tallied up every one.
Instead of one hundred one spots They averaged ninety six dots
Can they muzzle Spreckles’ Obsession with freckles Based on all the dog data they've got?
I need help to figure out the step by step solution.

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
a. H0: μ ≥ 101
b. Ha: μ < 101
c. Let X = the mean number of spots on an expensive Dalmatian.
d. Student’s t-distribution
e. –2.39
f. p-value = 0.0093
g. Check student’s solution.
h. i. Alpha: 0.05
.... ii. Decision: Reject the null hypothesis.
.... iii. Reason for decision: The p-value is less than 0.05.
.... iv. Conclusion: There is sufficient evidence to support the claim that the most expensive Dalmatians have less than 101 spots.
i. (91.854, 100.15)

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