You need to do a hypothesis test for population proportion, with: 

x = 34, n = 64, and p-hat = 

p (probability of success): 60%, or 0.6

q (probability of failure): 1 - p = .4

As x = 34, we find the Z-test Statistic, and then use that value to find the , or P-value 

Z-test Statistic = .

The 2-tailed P-Value for a Z-test Statistic of - 1.12 is .2628.

The P-value of .2628 > all significance levels that're usually used (.05, or 5%, .1, or 10%, and .005, or .5%). 

Therefore, with P-Value > ANY chosen significance level, then we: Fail to Reject Null, and conclude that there's INSUFFICIENT EVIDENCE

to reject her claim that 60 percent of the students who take her Elementary Statistics class go through life feeling more enriched. 

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