SOLUTION: Please help me on this i am confused on parts A through F. This is all one problem. 2. Using the following frequency table for a class of Beginning Algebra students� test score

Question 1042200: Please help me on this i am confused on parts A through F. This is all one problem.
2. Using the following frequency table for a class of Beginning Algebra students� test scores,
exam score 70 74 78 82 86 90 96 100
frequency 6 6 4 1 6 5 5 2
calculate the following:
a) average _________
b) 25th percentile _________
c) median _________

d) 75th percentile _________
e) 40th percentile _________
f) 80th percentile _________

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2. Using the following frequency table for a class of Beginning Algebra students� test scores,
exam score 70 74 78 82 86 90 96 100
frequency 6 6 4 1 6 5 5 2
Multiply each score number by its frequency
Totals.........420......444.....452.....82......516.....450.....480.....200
calculate the following:
a) average Add those "Total" numbers and divide by the sum of the frequency numbers to get:: 74.68___
b) 25th percentile = 0.25*35 = 8.75 = the 9th element is order = 74
---------------------------------------------------------
c) median is the middle score or aver of 17th and 18th = (82+86)/2 = 84
78d) 75th percentile = 0.75*35 = 27th element = 9
e) 40th percentile = 0.4*35 = 14 element = 78_________
f) 80th percentile = 96_________
Note: Some would say the answer to "f" is 90. Depends on how
you define percentile.
Cheers,
Stan H.

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