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Historically, 93% of the deliveries of an overnight mail service arrive before 10:30
the following morning. If a random sample of 500 deliveries is selected,
what is the probability the sample will have more than 95% of the deliveries arriving
before 10:30 the following morning?
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In order for the mathematical and the probabilistic meaning of this problem
would become more clear, let me re-formulate it in this way.
There is a binomial distribution with the individual probability of success of 0.93.
There is a random sample of 500 trials.
What is the probability of more than 0.95*500 = 475 successful trials ?
In this formulation, the probability is a standard binomial distribution problem
P = P(n=500; k>=476; p=0.93).
To facilitate calculations, I use online calculator at this site https://stattrek.com/online-calculator/binomial.aspx
It provides nice instructions and a convenient input and output for all relevant options/cases.
The resulting number is P = 0.02796 (rounded). ANSWER
Solved.