SOLUTION: 1,3,5 are the first three terms of a quadratic sequence the 7th term is 35 determine the 6th and 5th term of the sequence detrrmine the nth term

Question 1176929: 1,3,5 are the first three terms of a quadratic sequence the 7th term is 35 determine the 6th and 5th term of the sequence detrrmine the nth term
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
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1,3,5 are the first three terms of a quadratic sequence the 7th term is 35
determine the 6th and 5th term of the sequence detrrmine the nth term
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Hello, the very first statement in your post is not correct --- it is WRONG (!)

The three numbers 1, 3, 5 do not form   "a quadratic sequence".

They form a linear sequence, instead, which is the same as an arithmetic progression.

Use the terms properly, when you try to compose your own Math problem.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

Incorrect statement of the problem....

The given first three terms form a linear sequence, not a quadratic sequence. Graphed as the three points (1,1), (2,3), and (3,5), the three points will lie on a straight line; no quadratic will ever contain three points in a straight line.

So if the sequence is quadratic, the given first three terms are not right.

And if the given first three terms are right and the sequence is linear, then the 7th term is not 35.

So nothing can be done with the given information....

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