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lim (x-> -inf) (x^2+4^-x)/(x^2-4^x)
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To answer this question, you should apply your knowledge of Calculus.
The Calculus says that in the numerator, when x --> , the term dominates
and goes to infinity much fster than does.
In the denominator, when x --> , the term dominates comparing with .
Therefore, in whole, as x goes to , the given function behaves as .
When x --> , the numerator of this reduced fraction goes to infinity much faster than the denominator.
It gives the ANSWER: the given function goes to as x --> .
Solved.