SOLUTION: Determine the first three terms in the binomial expansion of (x-2y)^12
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Question 1139069: Determine the first three terms in the binomial expansion of (x-2y)^12
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
(x-2y)^12
:
The powers on each term in the expansion always add up to 12, and that the terms counted up from zero to 12. Note nCk = n!/(k! * (n-k)!)
:
The first three terms are
:
12C0(x)^(12 - 0)( - 2y)^0 + 12C1(x)^(12-1)( - 2y)^1 + 12C2(x)^(12-2)( - 2y)^2 =
:
x^12 -24(x)^11(y) +264(x)^10(y)^2
:
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