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According to Masterfoods, the company that manufactures M&M’s,
12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green.
[Round your answers to three decimal places, for example: 0.123]
(a) Compute the probability that two randomly selected peanut M&M’s are both brown.
P = 0.12*0.12 = 0.0144 = 0.014 (rounded as requested). ANSWER
( 0.12 = 12% )
(b) If you randomly select two peanut M&M’s, compute that probability that neither of them are orange.
P = (1-0.12)*(1-0.12) = 0.88*0.88 = 0.7744 = 0.774 (rounded as requested). ANSWER
(My calculations should be clear to you without further explanations !)
(c) If you randomly select two peanut M&M’s, compute that probability that at least one of them is orange.
P = 0.23*0.23 + 0.23*(1-0.23)
This time YOU make all necessary calculations and rounding on your own.
Happy calculations !
Who does not like M&M’s ? ? (rhetoric question . . . )