Question 1083377: Eexpand the (1+2x)7
Answer by natolino_2017(77)   (Show Source):
You can put this solution on YOUR website! Using the rule of Newton Binomial:
(1+2x)^7 = sum((7Ck)(1)^(7-k)(2x)^k from k= 0 to k = 7.
Se the (1)^k = 1 for any value ok k.
= 7C0 + 7C1(2x) + 7C2(4x^2) + 7C3(8x^3) + 7C4(16x^4) + 7C5(32x^5) + 7C6(64x^6) +7C7(128x^7)
= 1 + 14x + 84x^2 + 280x^3 + 560x^4 + 672x^5 + 448x^6 + 128x^7.
Remember that nCk = n!/((n-k)!(k!)) is n>=k and n and k are natural numbers or zero.
@natolino_
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