SOLUTION: Please I really need help.And it is about BINOMIAL THEOREM. SOLVE: (3x+2y)^10 please I need solution or step by step etc. :))) thank you very much.I hope you can help me. :

Question 1039780: Please I really need help.And it is about BINOMIAL THEOREM.
SOLVE: (3x+2y)^10

please I need solution or step by step etc. :))) thank you very much.I hope you can help me. :)
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Binomial theorem states
:
(a + b)^n = summation of k from 0 to n of nCk * a^(n-k) * b^k
:
(3x + 2y)^10, where a=3x, b=2y and n=10
:
(3x + 2y)^10 = 10C0(3x)^(10-0)(2y)^0 + 10C1(3x)^(10-1)(2y)^1 + 10C2(3x)^(10-2)(2y)^2 + 10C3(3x)^(10-3)(2y)^3 + 10C4(3x)^(10-4)(2y)^4 + 10C5(3x)^(10-5)(2y)^5 + 10C6(3x)^(10-6)(2y)^6 + 10C7(3x)^(10-7)(2y)^7 + 10C8(3x)^(10-8)(2y)^8 + 10C9(3x)^(10-9)(2y)^9 + 10C10(3x)^(10-10)(2y)^10
:
note that nCk = n! / (k! * (n-k)!)
:

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