```Question 136436
Well first we need to find the slope of the line between those two points.  To do that we use the slope formula which is:<br>

m = (y2-y1)/(x2-x1) where<br>

x1 = -3
y1 = 5
x2 = 2
y2 = -5<br>

so plugging in those numbers we get:
m = (y2-y1)/(x2-x1)
m = (-5-5)/(2-(-3))
m = -10/5
m = -2<br>

Now we can find the slope intercept form of a line in two ways:<br>

Method 1: Solve y = mx+b for b
Since we know that y=mx+b and we have numbers for y,m, and x we can plug those into the formula and solve for b.<br>

y = mx + b
-5 = -2(2) + b
-5 = -4 + b
-1 = b<br>

now plugging in your m and b values into the y=mx+b gives you the equation of the line. y = -2x - 1<br>

Method 2: use the point slope formula and solve for y.<br>

the is another formula that you might not have learned yet, its the point slope formula:<br>

y-y1=m(x-x1) where
x1 = -3
y1 = 5
m = -2
now plugging in you get:<br>

y-5 = -2(x-(-3))
y-5 = -2(x+3)
y-5 = -2x-6
y = -2x - 1<br>

So the equation of the line though the two given points is y = -2x-1.  ```