Question 136138
Given: {{{((n-2)/(n+4)) + ((n^2 + 5n + 10)/(n+4)) }}}

Before one can add fractions, they must have a common denominator. In this problem, each fraction has a denominator of {{{(n+4)}}}. So, the two fractions can be added in their current form

{{{((n-2)/(n+4)) + ((n^2 + 5n + 10)/(n+4)) }}}
{{{((n-2) + (n^2 + 5n + 10))/(n+4)}}}

Now you can collect like terms 
{{{(n^2 + 5n + n + 10 -2)/(n+4)}}}
{{{(n^2 + 6n + 8)/(n+4)}}}

factor the numerator
{{{((n+4)(n+2))/(n+4) }}}
{{{n+2}}}  where n!= -4