Question 135806
{{{x^3-7x^2+6x=0}}}

First off, we can see by inspection that one answer is x=0
Factor x out

{{{x(x^2-7x+6)=0}}}
we can factor {{{x^2-7x+6}}}; {{{(x-1)(x-6)}}}.  So now we have:


{{{x(x-1)(x-6)=0}}}
x=0,
x-1=0;  x=1
x-6=0;  x=6

Hope this helps----ptaylor