Question 134722
You need to use more parens. It is hard to know what your question really is without them.

I'll assume you meant {{{(1-(5/(a-1))) / (3 - (2/(a-1)))}}}

you need to find a common denominator for both the numberator terms and the denominator terms.

{{{((1(a-1)-5)/(a-1)) / ((3(a-1) - 2)/(a-1))}}}

Turns out that both fractions have the same denominator {{{(a-1)}}}

Dividing two fractions is the same as multipling the numerator fraction by the inverse of the denominator fraction.

{{{((1(a-1)-5)/(a-1)) * ((a-1)/(3(a-1) - 2))}}}


Now {{{(a-1)/(a-1)}}} = 1  so those terms "cancel", leaving

{{{((1(a-1)-5)/(3(a-1) - 2))}}}

{{{(a - 1 - 5)/ (3a -3 -2)}}}
{{{ (a-6) / (3a-5) }}}