Question 134492


Looking at {{{14x^2-53x+14}}} we can see that the first term is {{{14x^2}}} and the last term is {{{14}}} where the coefficients are 14 and 14 respectively.


Now multiply the first coefficient 14 and the last coefficient 14 to get 196. Now what two numbers multiply to 196 and add to the  middle coefficient -53? Let's list all of the factors of 196:




Factors of 196:

1,2,4,7,14,28,49,98


-1,-2,-4,-7,-14,-28,-49,-98 ...List the negative factors as well. This will allow us to find all possible combinations


These factors pair up and multiply to 196

1*196

2*98

4*49

7*28

14*14

(-1)*(-196)

(-2)*(-98)

(-4)*(-49)

(-7)*(-28)

(-14)*(-14)


note: remember two negative numbers multiplied together make a positive number



Now which of these pairs add to -53? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -53


<table border="1"><th>First Number</th><th>Second Number</th><th>Sum</th><tr><td align="center">1</td><td align="center">196</td><td>1+196=197</td></tr><tr><td align="center">2</td><td align="center">98</td><td>2+98=100</td></tr><tr><td align="center">4</td><td align="center">49</td><td>4+49=53</td></tr><tr><td align="center">7</td><td align="center">28</td><td>7+28=35</td></tr><tr><td align="center">14</td><td align="center">14</td><td>14+14=28</td></tr><tr><td align="center">-1</td><td align="center">-196</td><td>-1+(-196)=-197</td></tr><tr><td align="center">-2</td><td align="center">-98</td><td>-2+(-98)=-100</td></tr><tr><td align="center">-4</td><td align="center">-49</td><td>-4+(-49)=-53</td></tr><tr><td align="center">-7</td><td align="center">-28</td><td>-7+(-28)=-35</td></tr><tr><td align="center">-14</td><td align="center">-14</td><td>-14+(-14)=-28</td></tr></table>



From this list we can see that -4 and -49 add up to -53 and multiply to 196



Now looking at the expression {{{14x^2-53x+14}}}, replace {{{-53x}}} with {{{-4x+-49x}}} (notice {{{-4x+-49x}}} adds up to {{{-53x}}}. So it is equivalent to {{{-53x}}})


{{{14x^2+highlight(-4x+-49x)+14}}}



Now let's factor {{{14x^2-4x-49x+14}}} by grouping:



{{{(14x^2-4x)+(-49x+14)}}} Group like terms



{{{2x(7x-2)-7(7x-2)}}} Factor out the GCF of {{{2x}}} out of the first group. Factor out the GCF of {{{-7}}} out of the second group



{{{(2x-7)(7x-2)}}} Since we have a common term of {{{7x-2}}}, we can combine like terms


So {{{14x^2-4x-49x+14}}} factors to {{{(2x-7)(7x-2)}}}



So this also means that {{{14x^2-53x+14}}} factors to {{{(2x-7)(7x-2)}}} (since {{{14x^2-53x+14}}} is equivalent to {{{14x^2-4x-49x+14}}})




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     Answer:

So {{{14x^2-53x+14}}} factors to {{{(2x-7)(7x-2)}}}