Question 20346
7 {{{sqrt(12)}}}+4{{{sqrt(3)}}}
12 can be broken up as 4*3;
7{{{sqrt(4*3)}}}+4{{{sqrt(3)}}}
4 is a perfect square = 2, so we have;
7*2{{{sqrt(3)}}}+4{{{sqrt(3)}}}
Multiply 7*2=14 so we have;
14{{{sqrt(3)}}}+4{{{sqrt(3)}}}
Now we can add them together because they are like terms;
18{{{sqrt(3)}}}
Hope you understand
=)