Question 126066


Let's denote the first point (-1,-2) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=-1] and *[Tex \LARGE y_{1}=-2]


Now let's denote the second point (3,-2) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=3] and *[Tex \Large y_{2}=-2]




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{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(-2--2)/(3--1)}}} Plug in {{{y[2]=-2}}},{{{y[1]=-2}}},{{{x[2]=3}}},{{{x[1]=-1}}}



{{{m=0/4}}} Subtract the terms in the numerator {{{-2--2}}} to get {{{0}}}.  Subtract the terms in the denominator {{{3--1}}} to get {{{4}}}

  

{{{m=0}}} Reduce


  

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Answer:


So the slope of the line through the points (-1,-2) and (3,-2) is {{{m=0}}}