Question 2221
any quadratic of the form {{{ax^2 + bx + c = 0 }}} can be solved by putting the values of a,b and c into the quadratic formula:

x = {{{(-b +- sqrt(b^2 - 4ac))/(2a)}}}

so, put your values (taken from the equation {{{x^2 +3x-10=0}}}) into that formula:

x = {{{(-3 +- sqrt(3^2 - 4*1*(-10)))/(2*1)}}}

x = {{{(-3 +- sqrt(9 + 40))/(2)}}}

x = {{{(-3 +- sqrt(49))/2}}}

x = {{{(-3 +- 7)/2}}}

so either x={{{(-3 + 7)/2}}} or x={{{(-3 - 7)/2}}}

which gives x=4/2 or -10/2
so x= 2 or x=-5



jon.