Question 123139

{{{5x-y=-5 }}}.................(1)

{{{3x-5y=-3}}}.................(2)
--------------------------------------------

{{{5x-y=-5 }}}.................(1).......solve for {{{y}}}


{{{5x + 5= y}}}..........substitute in (2) and solve (2) for {{{x}}}

{{{3x- 5(5x + 5)=-3}}}

{{{3x -25x - 25 =-3}}}

{{{ -22x = -3+25}}}

{{{ -22x = 22}}}

{{{ x = 22/-22 }}}


{{{ x = -1}}}



now find {{{y}}}

{{{y = 5x + 5}}}..........

{{{y = 5(-1) + 5}}}..........

{{{y = -5+ 5}}}..........

{{{y = 0}}}..........

check:


{{{5(-1)- 0= -5 }}}.................(1)


{{{-5 = -5 }}}


{{{3(-1)- 5(0) = -3}}} .................(2)

{{{-3 = -3}}}