Question 120169
{{{matrix(10,2,44,8,45,9,46,10,green(47),green(11),48,12,green(49),green(13),50,5,51,6,green(52),green(7),53,8)}}}


The table has the integers and the sum of their digits.  Three of these have a sum of digits that is prime, 47, 49, and 52.


47 is prime so it has only two factors, itself and 1


{{{49=7^2}}} so it only has two prime factors, 7 and 7, plus itself and 1.  But you can't really call 1 a factor, so this has just 3 factors


{{{52=2*2*13}}} and has three prime factors, 2, 2, and 13, plus itself and 1.  Therefore 4 factors.