Question 119534
Assume you mean:
{{{2/((5x+ 15))}}} + {{{5/((x+3))}}}
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We can factor the 1st denominator
{{{2/(5(x+3))}}} + {{{5/((x+3))}}}
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The common denominator is 5(x+3), so we have:
{{{((2 + 5(5)))/(5(x+3))}}} = {{{27/(5(x+3))}}}
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;
:
{{{((x+2))/((x^2+4x +3))}}} - {{{6/((x+3))}}}
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The first denominator will factor here also:
{{{((x+2))/((x+1)(x+3))}}} - {{{6/((x+3))}}}
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The common denominator will be (x+1)(x+3), right?
{{{((x+2) - 6(x+1))/((x+1)(x+3))}}} = {{{((x + 2 - 6x - 6))/((x+1)(x+3))}}} = {{{((-5x - 4))/((x+1)(x+3))}}}
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Did this help? Do you understand this now? Let me know.
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