Question 118664
Remember, when you multiply expressions like {{{x^3}}} and {{{x^2}}}, you simply add the exponents. So {{{x^3*x^2=x^(3+2)=x^5}}}


Now when you divide, just undo the multiplication by dividing. In other words, {{{x^3/x^2=x^(3-2)=x^1=x}}}


Now if you divide 2 equal expressions, then you will always get 1 (ie {{{x/x=1}}}). So something like {{{x^3/x^3=x^(3-3)=x^0=1}}}


So this shows why {{{a^0 =1}}} for any nonzero value of a. Now I'll let you think this question over: why does "a" have to be nonzero?