Question 118311
*[Tex \Large x^2=49]  Start with the given equation



*[Tex \Large sqrt{x^2}=\pm sqrt{49}] Take the square root of both sides



*[Tex \Large x=\pm 7] Take the square root of {{{x^2}}} to get {{{x}}} and take the square root of 49 to get  plus or minus 7


So our answer is *[Tex \Large x=\pm 7] which is really {{{x=-7}}} or {{{x=7}}}