Question 118184
Use method of substitution to solve system:

x-y^3=1
2x=9y^2+2

This is what I have done:
x=1+y^3
2(1+y^3)= 9y^2+2
2+2y^3 = 9y^2+2
2y^3=9y^2
2y^3-9y^2=0
y^2(2y-9) = 0
y = 0 or y = 9/2
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Now solve for "x":
If y = 0, x = 0^3+1 = 1
If y = (9/2), x = (9/2)^3+1 = 729/8+1 = 737/8= 91 1/8
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Cheers,
Stan H.