Question 118012
*[invoke equation_parallel_or_perpendicular "perpendicular", -3, 12, 2, -3]


Now let's convert {{{y=(1/3)x-11/3}}} to standard form


*[invoke converting_linear_equations "slope-intercept_to_standard", 1, 2, 3, "1/3", "-11/3"]


Since the answer is {{{x-3y=11}}}, I'm assuming that the book wants A to be positive.



{{{-1(-x+3y)=(-1)(-11)}}} Multiply both sides of {{{-x+3y=-11}}} by -1 


{{{x-3y=11}}} Distribute and multiply



So the answer is {{{x-3y=11}}}