Question 17581
{{{(b^2/4a^2)-(c/a)}}}
The LCM of 4a^2 and a is 4a^2
Then,
{{{(b^2-4ac)/(4a^2)}}}
[to convert a to 4a^2 we need to multiply by '4a',hence the numerator is also multiplied by 4a]
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In other form,
{{{(b^2/4a^2)-((c/a)*(4a/4a))}}}
[Multiplying by 4a/4a is the same as multiplying by one. Hence the fraction does not change.]
{{{(b^2/4a^2)-(4ac/4a^2)}}}
[Now since the denominators are the same,we can subtract]
{{{(b^2-4ac)/(4a^2)}}}
[And this is our final expression]
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Hope this helps,
Prabhat