Question 17593
Solve for y:

3x+4y = 12


Subtract 3x from each side:
3x-3x + 4y = -3x + 12
4y = -3x + 12


Divide both sides by 4 (it's best in this case to divide each term by 4):  
{{{(4y)/4 = (-3x)/4 + 12/4 }}}
{{{y = (-3/4)x + 3}}}


R^2 at SCC